Chapter 6: Problem 6
Find all antiderivatives of each following function: $$f(x)=-4 x$$
Short Answer
Expert verified
The antiderivative of \( f(x) = -4x \) is \( F(x) = -2x^2 + C \), where C is a constant.
Step by step solution
01
- Identify the given function
The given function is \( f(x) = -4x \). To find the antiderivative, we need to determine a function whose derivative is \(-4x\).
02
- Apply the power rule for antiderivatives
The power rule for antiderivatives states that if \( f(x) = x^n \), the antiderivative is \[ F(x) = \frac{x^{n+1}}{n+1} + C \] where C is the constant of integration. Here, \( f(x) = -4x = -4x^1 \), so we will use this rule.
03
- Integrate the function
We apply the antiderivative power rule: \[ \int -4x \, dx = -4 \int x^1 \, dx = -4 \left( \frac{x^{1+1}}{1+1} \right) + C = -4 \left( \frac{x^2}{2} \right) + C = -2x^2 + C \] Here, C is the constant of integration.
04
- State the general form of the antiderivative
The general form of the antiderivative of \( f(x) = -4x \) is given by \[ F(x) = -2x^2 + C \] where C is an arbitrary constant.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The power rule is a fundamental tool in calculus for both differentiation and integration. When solving antiderivatives, we use the power rule to find the integral of functions in the form of a power of x.
Specifically, when integrating a function like \(x^n\), the power rule states:
 \[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \] Â
How do we apply this? Let's consider our example function \(f(x) = -4x\)
1. Rewrite \( -4x \) as \( -4x^1 \).
2. Apply the power rule \( \int x^1 \, dx = \frac{x^{1+1}}{1+1} + C = \frac{x^2}{2} + C \).
3. Multiply by the constant coefficient, which is -4: \( -4 \cdot \frac{x^2}{2} \), simplifying to \( -2x^2 \).
Therefore, \( \int -4x \, dx = -2x^2 + C \).
By understanding the power rule, we can handle more complex problems easily by just managing the exponent changes.
Specifically, when integrating a function like \(x^n\), the power rule states:
 \[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \] Â
How do we apply this? Let's consider our example function \(f(x) = -4x\)
1. Rewrite \( -4x \) as \( -4x^1 \).
2. Apply the power rule \( \int x^1 \, dx = \frac{x^{1+1}}{1+1} + C = \frac{x^2}{2} + C \).
3. Multiply by the constant coefficient, which is -4: \( -4 \cdot \frac{x^2}{2} \), simplifying to \( -2x^2 \).
Therefore, \( \int -4x \, dx = -2x^2 + C \).
By understanding the power rule, we can handle more complex problems easily by just managing the exponent changes.
Constant of Integration
Integrating a function always involves an unknown constant, known as the constant of integration. This is because when you take the derivative of a constant, you get zero, meaning the original function could have been shifted up or down.
For our example with \(f(x) = -4x\), after integrating, we get:
\[ F(x) = -2x^2 + C \]
The +' \(C\)' represents an infinite number of possible antiderivatives, each differing by a constant value. Without this constant, you'd miss out on representing all possible solutions for the antiderivative.
For example, both \(-2x^2 + 3\) and \(-2x^2 - 5\) are antiderivatives of \( -4x \). They only differ by a constant, represented as \( C \). This constant ensures that all possible vertical shifts of the antiderivative are covered.
For our example with \(f(x) = -4x\), after integrating, we get:
\[ F(x) = -2x^2 + C \]
The +' \(C\)' represents an infinite number of possible antiderivatives, each differing by a constant value. Without this constant, you'd miss out on representing all possible solutions for the antiderivative.
For example, both \(-2x^2 + 3\) and \(-2x^2 - 5\) are antiderivatives of \( -4x \). They only differ by a constant, represented as \( C \). This constant ensures that all possible vertical shifts of the antiderivative are covered.
Integral
The integral of a function represents the antiderivative, and it essentially 'reverses' differentiation. When you integrate a function \(f(x)\) over a variable, you're finding a new function whose derivative is \(f(x)\).
Let's revisit our example \( f(x) = -4x \). To find the integral (antiderivative):
1. Recognize that we are looking for a function \(F(x)\) such that \( F'(x) = f(x) = -4x \).
2. Use the power rule to integrate: \[ \int -4x \, dx = -2x^2 + C \]
3. The integral sign \( \int \) indicates that we are finding the antiderivative.
The result \( -2x^2 + C \) is the function whose derivative brings us back to \( -4x \).
In calculus, integrals come in two types:
Let's revisit our example \( f(x) = -4x \). To find the integral (antiderivative):
1. Recognize that we are looking for a function \(F(x)\) such that \( F'(x) = f(x) = -4x \).
2. Use the power rule to integrate: \[ \int -4x \, dx = -2x^2 + C \]
3. The integral sign \( \int \) indicates that we are finding the antiderivative.
The result \( -2x^2 + C \) is the function whose derivative brings us back to \( -4x \).
In calculus, integrals come in two types:
- Indefinite integrals (which include the constant of integration).
- Definite integrals (which calculate the area under the curve between two points).