Chapter 1: Problem 34
In Exercises \(33-36\), refer to a line of slope \(m\). If you begin at a point on the line and move \(h\) units in the \(x\) -direction, how many units must you move in the \(y\) -direction to return to the line? \(m=2, h=\frac{1}{2}\)
Short Answer
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Step by step solution
01
- Understand the Given Values
Identify the given values. The slope of the line is denoted as \( m \) and it is given that \( m = 2 \). The horizontal distance moved, denoted as \( h \), is given as \( h = \frac{1}{2} \).
02
- Recall the Slope Formula
Recall that the slope \( m \) of a line is defined as the change in \( y \)-direction divided by the change in \( x \)-direction: \[ m = \frac{\Delta y}{\Delta x} \]
03
- Solve for the Change in y-direction
We need to find how many units we must move in the \( y \)-direction to stay on the line after moving \( h \) units in the \( x \)-direction. Using the slope formula from the previous step, we can rearrange it to solve for \( \Delta y \): \[ \Delta y = m \cdot \Delta x \] Substituting the given values \( m = 2 \) and \( \Delta x = h = \frac{1}{2} \), we get: \[ \Delta y = 2 \cdot \frac{1}{2} \]
04
- Calculate the Result
Perform the multiplication: \[ \Delta y = 2 \cdot \frac{1}{2} = 1 \] Therefore, you must move 1 unit in the \( y \)-direction.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
slope of a line
The 'slope of a line' is a fundamental concept in algebra. It represents the steepness of a line. You can think of it as how much the line slants upward or downward. The slope is usually represented by the letter \( m \). In mathematics, the slope of a line is defined as the ratio of the change in the y-direction to the change in the x-direction.
Specifically, the slope \( m \) is defined by the formula: \[ m = \frac{\Delta y}{\Delta x} \] where \( \Delta y \) is the change in the y-coordinates and \( \Delta x \) is the change in the x-coordinates. This formula tells us that for every unit you move horizontally to the right (increasing \( x \)-direction), the line moves up or down by \( \Delta y \) units.
Knowing the slope helps in plotting lines and understanding their behaviour. For instance, a slope of 2 means that for every one unit you move to the right, the line goes up by 2 units. It's like a simple step-by-step guide to drawing a line on a graph.
Specifically, the slope \( m \) is defined by the formula: \[ m = \frac{\Delta y}{\Delta x} \] where \( \Delta y \) is the change in the y-coordinates and \( \Delta x \) is the change in the x-coordinates. This formula tells us that for every unit you move horizontally to the right (increasing \( x \)-direction), the line moves up or down by \( \Delta y \) units.
Knowing the slope helps in plotting lines and understanding their behaviour. For instance, a slope of 2 means that for every one unit you move to the right, the line goes up by 2 units. It's like a simple step-by-step guide to drawing a line on a graph.
change in y-direction
Understanding the 'change in y-direction' is crucial when working with slopes. The change in y-direction, symbolized as \( \Delta y \), refers to the vertical distance moved on the graph. It helps determine how high or low the line will go when you move horizontally.
Imagine you start at a certain point on a line. If the slope of the line is 2, this means for every unit you move horizontally (rightward), your height (y-coordinate) will increase by 2 units. This increase can be calculated using the rearranged slope formula: \[ \Delta y = m \cdot \Delta x \]
Here, \( \Delta y \) shows the change in the y-coordinate, \( m \) is the slope, and \( \Delta x \) represents the horizontal distance moved (change in x-direction). To continue, if the slope \( m = 2 \) and the horizontal distance \( \Delta x = \frac{1}{2} \), then: \[ \Delta y = 2 \cdot \frac{1}{2} = 1 \]
So, you would move 1 unit upward in the y-direction.
Imagine you start at a certain point on a line. If the slope of the line is 2, this means for every unit you move horizontally (rightward), your height (y-coordinate) will increase by 2 units. This increase can be calculated using the rearranged slope formula: \[ \Delta y = m \cdot \Delta x \]
Here, \( \Delta y \) shows the change in the y-coordinate, \( m \) is the slope, and \( \Delta x \) represents the horizontal distance moved (change in x-direction). To continue, if the slope \( m = 2 \) and the horizontal distance \( \Delta x = \frac{1}{2} \), then: \[ \Delta y = 2 \cdot \frac{1}{2} = 1 \]
So, you would move 1 unit upward in the y-direction.
horizontal distance
The 'horizontal distance' in mathematics refers to how far you've moved along the x-axis. It's often symbolized as \( \Delta x \). This distance plays a key role when you're trying to find out how much you need to move vertically to stay on a given line.
For instance, say you move a certain number of units to the right (positive \( x \)-direction). Without changing the vertical position, this horizontal movement affects how high or low you'll need to adjust next. If you know the slope of the line and move horizontally by a specific amount, you can calculate the required vertical movement to stay on the line using the slope formula.
In our example, the slope \( m = 2 \) and the horizontal distance \( h = \frac{1}{2} \). According to the slope formula rearranged for vertical distance, \( \Delta y = m \cdot \Delta x \), substituting in our values gives us: \[ \Delta y = 2 \cdot \frac{1}{2} = 1 \]
This means if you move \( \frac{1}{2} \) units horizontally, you need to move 1 unit vertically to stay on the line.
For instance, say you move a certain number of units to the right (positive \( x \)-direction). Without changing the vertical position, this horizontal movement affects how high or low you'll need to adjust next. If you know the slope of the line and move horizontally by a specific amount, you can calculate the required vertical movement to stay on the line using the slope formula.
In our example, the slope \( m = 2 \) and the horizontal distance \( h = \frac{1}{2} \). According to the slope formula rearranged for vertical distance, \( \Delta y = m \cdot \Delta x \), substituting in our values gives us: \[ \Delta y = 2 \cdot \frac{1}{2} = 1 \]
This means if you move \( \frac{1}{2} \) units horizontally, you need to move 1 unit vertically to stay on the line.