Chapter 1: Problem 34
Determine the value of \(a\) that makes the function \(f(x)\) continuous at \(x=0\). \(f(x)=\left\\{\begin{array}{ll}2(x-a) & \text { for } x \geq 0 \\ x^{2}+1 & \text { for } x<0\end{array}\right.\)
Short Answer
Expert verified
a = -\frac{1}{2}
Step by step solution
01
Understand the Definition of Continuity
A function is continuous at a point if the left-hand limit (as it approaches from the negative side), the right-hand limit (as it approaches from the positive side), and the function's value at that point are all equal.
02
Identify the Right-Hand Limit
Evaluate the limit of the function as it approaches 0 from the positive side: \ \( \text{Right-hand limit} = \ \ \text{lim}_{x \to 0^+} 2(x - a) = 2(0 - a) = -2a \ \)
03
Identify the Left-Hand Limit
Evaluate the limit of the function as it approaches 0 from the negative side: \ \ \( \text{Left-hand limit} = \ \ \text{lim}_{x \to 0^-} (x^2 + 1) = 0^2 + 1 = 1 \ \)
04
Set the Limits Equal to Each Other
For the function to be continuous at x=0, set the right-hand limit equal to the left-hand limit: \ \ \(-2a = 1\)
05
Solve for a
Solve the equation: \ \ \(-2a = 1\) \ \ Divide both sides by -2: a = -\frac{1}{2}
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuous Functions
A continuous function is a function that has no breaks, jumps, or holes in its graph. If you can draw the function's graph without lifting your pen, then the function is continuous. Mathematically, a function \( f(x) \) is continuous at a point \( x = c \) if the following conditions are met:
- The function is defined at that point, \( f(c) \) exists.
- The limit as \( x \) approaches \( c \) from the left, \( \text{lim}_{x \to c^-} f(x) \), exists.
- The limit as \( x \) approaches \( c \) from the right, \( \text{lim}_{x \to c^+} f(x) \), exists.
- The value of the function at \( c \) equals the left-hand limit and the right-hand limit: \( f(c) = \text{lim}_{x \to c^-} f(x) = \text{lim}_{x \to c^+} f(x) \).
Limits
Limits are fundamental in calculus and play a critical role in defining derivatives, integrals, and continuity. The limit of a function \( f(x) \) as \( x \) approaches a specific value \( c \) is written as \[ \text{lim}\thinspace_{x \to c} f(x) \]. This represents the value that \( f(x) \) gets closer to as \( x \) gets closer to \( c \). Here are some key points about limits:
- Right-Hand Limit: The limit as \( x \) approaches \( c \) from the positive side, noted as \[ \text{lim}\thinspace_{x \to c^+} f(x) \].
- Left-Hand Limit: The limit as \( x \) approaches \( c \) from the negative side, noted as \[ \text{lim}\thinspace_{x \to c^-} f(x) \].
Evaluating Limits
To determine the value that makes a function continuous at a certain point, you often need to evaluate its limits. Let's break down how we apply this to the provided exercise:
Right-Hand Limit
We need to find the limit of the function \( f(x) \) as \( x \) approaches 0 from the positive side:
\[ \text{lim}\thinspace_{x \to 0^+} 2(x - a) = 2(0 - a) = -2a \]
Left-Hand Limit
Next, we find the limit of the function \( f(x) \) as \( x \) approaches 0 from the negative side:
\[ \text{lim}\thinspace_{x \to 0^-} (x^2 + 1) = 0^2 + 1 = 1 \]
Setting the Limits Equal
For the function \( f(x) \) to be continuous at \( x = 0 \), the right-hand and left-hand limits must be equal. Hence,
-2a = 1
Solving for \( a \):
Finally, solve for \( a \):
\[ a = - \frac{1}{2} \]
By following these steps, we ensure the function is continuous at \( x = 0 \). Evaluating limits is a powerful technique in ensuring the smooth behavior of functions and solving such problems systematically.
Right-Hand Limit
We need to find the limit of the function \( f(x) \) as \( x \) approaches 0 from the positive side:
\[ \text{lim}\thinspace_{x \to 0^+} 2(x - a) = 2(0 - a) = -2a \]
Left-Hand Limit
Next, we find the limit of the function \( f(x) \) as \( x \) approaches 0 from the negative side:
\[ \text{lim}\thinspace_{x \to 0^-} (x^2 + 1) = 0^2 + 1 = 1 \]
Setting the Limits Equal
For the function \( f(x) \) to be continuous at \( x = 0 \), the right-hand and left-hand limits must be equal. Hence,
-2a = 1
Solving for \( a \):
Finally, solve for \( a \):
\[ a = - \frac{1}{2} \]
By following these steps, we ensure the function is continuous at \( x = 0 \). Evaluating limits is a powerful technique in ensuring the smooth behavior of functions and solving such problems systematically.