Chapter 3: Problem 4
Find the general form of the function that satisfies \(d P / d t=-3 P(t)\)
Short Answer
Expert verified
The general solution is \( P(t) = Ce^{-3t} \), where \( C \) is a constant.
Step by step solution
01
Understand the Equation
The given differential equation is \( \frac{dP}{dt} = -3P(t) \). This is a first-order linear differential equation that can be solved using separation of variables or by recognizing it as a standard form of exponential growth or decay.
02
Write the Differential Equation in Separation of Variables Form
Rearrange the terms to separate the variables related to \( P \) and \( t \). This gives \( \frac{dP}{P} = -3 \, dt \).
03
Integrate Both Sides
Integrate both sides to find \( P \) as a function of \( t \). The integral of \( \frac{dP}{P} \) is \( \ln |P| \), and the integral of \(-3 \, dt\) is \(-3t + C\), where \( C \) is the integration constant.
04
Solve for \( P(t) \)
Exponentiate both sides to solve for \( P(t) \). This gives \( |P| = e^{-3t+C} \). Recognizing that \( e^{C} \) is just another constant \( C' \), we have \( P(t) = C'e^{-3t} \). Since \( P \) can be positive or negative based on the initial condition, we write \( P(t) = Ce^{-3t} \), where \( C \) is a constant that could be positive or negative.
05
Conclude the General Solution
The general solution of the differential equation \( \frac{dP}{dt} = -3P(t) \) is \( P(t) = Ce^{-3t} \), where \( C \) is an arbitrary constant determined by initial conditions or boundary values.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order Differential Equation
First-order differential equations like the one in the exercise are equations that involve the first derivative of a function. In this case, the function is denoted by \( P(t) \), and the exercise gives us \( \frac{dP}{dt} = -3 P(t) \). This equation tells us how \( P(t) \) changes with respect to time \( t \). Essentially, the rate of change of \( P(t) \) is proportional to its current value, with a proportionality constant of \(-3\) in this case.
The negative sign in the equation signals that \( P(t) \) decreases over time, particularly at a rate three times its current value. Understanding these basic elements of a first-order differential equation helps in recognizing how these types of equations describe scenarios where a quantity diminishes or escalates based on its current state.
The negative sign in the equation signals that \( P(t) \) decreases over time, particularly at a rate three times its current value. Understanding these basic elements of a first-order differential equation helps in recognizing how these types of equations describe scenarios where a quantity diminishes or escalates based on its current state.
Separation of Variables
Separation of variables is a method used to solve differential equations, particularly useful for first-order equations. The main idea is to manipulate the equation so that all terms involving one variable (here, \( P \)) are on one side, and all terms involving the other variable (here, \( t \)) are on the other side.
In the exercise, we rearrange \( \frac{dP}{dt} = -3 P(t) \) to \( \frac{dP}{P} = -3 \, dt \). This process sets the stage for integration, making it possible to find solutions by integrating both sides separately.
In the exercise, we rearrange \( \frac{dP}{dt} = -3 P(t) \) to \( \frac{dP}{P} = -3 \, dt \). This process sets the stage for integration, making it possible to find solutions by integrating both sides separately.
- By integrating \( \frac{dP}{P} \), we obtain \( \ln |P| \).
- By integrating \(-3 \, dt \), results in \(-3t + C\), where \( C \) is the constant of integration.
Exponential Decay
The concept of exponential decay is illustrated perfectly by the resolved form of this differential equation: \( P(t) = Ce^{-3t} \). Exponential decay occurs when the value of a quantity decreases at a rate proportional to its current value.
The formula \( P(t) = Ce^{-3t} \) models how \( P \) decreases exponentially over time. Here, \( e^{-3t} \) represents the decay factor that shrinks the function value, indicating a rapid decline as time progresses since the exponent \(-3t\) increases negatively with higher \( t \) value.
The formula \( P(t) = Ce^{-3t} \) models how \( P \) decreases exponentially over time. Here, \( e^{-3t} \) represents the decay factor that shrinks the function value, indicating a rapid decline as time progresses since the exponent \(-3t\) increases negatively with higher \( t \) value.
- The constant \( C \) alters the initial state or size of \( P(t) \). Larger initial values imply a larger \( C \).