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Find an expression relating the exponential growth rate \(k\) and the quadrupling time \(T_{4}\).

Short Answer

Expert verified
The exponential growth rate \( k \) is \( k = \frac{\ln(4)}{T_4} \).

Step by step solution

01

Understand Exponential Growth

Exponential growth can be described by the function \( y(t) = y_0 e^{kt} \), where \( y_0 \) is the initial amount, \( k \) is the growth rate, and \( t \) is time.
02

Define Quadrupling Time

The quadrupling time \( T_4 \) is the time it takes for the initial amount \( y_0 \) to quadruple. This means \( y(T_4) = 4y_0 \).
03

Set Up the Equation for Quadrupling

Using the exponential growth function, set up the equation: \( 4y_0 = y_0 e^{kT_4} \).
04

Simplify the Equation

Divide both sides of the equation by \( y_0 \): \( 4 = e^{kT_4} \).
05

Take the Natural Logarithm

Take the natural logarithm of both sides to solve for \( kT_4 \): \( \ln(4) = kT_4 \).
06

Solve for the Growth Rate \( k \)

Rearrange the equation to express \( k \) in terms of \( T_4 \): \( k = \frac{\ln(4)}{T_4} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Growth Rate
Exponential growth is a fundamental concept often seen in real-world scenarios like population growth, finance, and biology. The growth rate, denoted by the variable \( k \), tells us how quickly the amount is increasing over time. It is a constant that appears in the exponential growth function, which is typically written as \( y(t) = y_0 e^{kt} \). This formula considers:
  • \( y(t) \): the amount at time \( t \)
  • \( y_0 \): the initial amount
  • \( e \): the base of the natural logarithm (approximately 2.718)
  • \( k \): the growth rate
  • \( t \): time
The growth rate is crucial, as it gives insight into how fast the quantity is multiplying. A higher \( k \) means an increased speed of growth, indicating rapid exponential expansion. Understanding the growth rate allows us to predict future quantities by calculating how much an amount will grow over a specified period.
Quadrupling Time
Quadrupling time, denoted as \( T_4 \), defines how long it takes for a quantity to increase fourfold through exponential growth. In context, if you start with an initial amount \( y_0 \), quadrupling time is when your amount becomes \( 4y_0 \). The concept of quadrupling time helps us grasp how quickly growth is happening without having to monitor it continuously. Let's explore this through the exponential growth equation:Starting with the equation \( 4y_0 = y_0 e^{kT_4} \), we isolate what happens at quadrupling:
  • Dividing both sides by \( y_0 \) results in \( 4 = e^{kT_4} \)
  • This equation solidifies the definition: the time variable \( T_4 \) that makes the quantity four times the initial value
In various applications, knowing the quadrupling time can be crucial for strategic planning, like predicting population increases or anticipating financial investments.
Natural Logarithm
The natural logarithm, often symbolized as \( \ln \), is integral to solving equations in exponential growth. The natural logarithm has a unique base \( e \), which is a mathematical constant approximately equal to 2.718. It is commonly used in natural growth processes due to its intrinsic properties.In our context of quadrupling time, we solved \( 4 = e^{kT_4} \) by taking the natural logarithm of both sides:
  • The result is \( \ln(4) = kT_4 \)
  • This step transforms the problem into a manageable linear equation
Using the natural logarithm is crucial because it offers a straightforward method to "undo" the exponential aspect in the equation, simplifying our task of finding the growth rate \( k \). The relationship between exponential functions and their logarithms makes understanding one vital in solving for the other.

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Most popular questions from this chapter

The Rule of 70. The relationship between doubling time \(T\) and growth rate \(k\) is the basis of the Rule of \(70 .\) Since $$ T=\frac{\ln 2}{k}=\frac{0.693147}{k}=\frac{69.3147}{100 k} \approx \frac{70}{100 k} $$ we can estimate the length of time needed for a quantity to double by dividing the growth rate \(k\) (expressed as a percentage) into \(70 .\)

The population of the United States in 1776 was about 2,508,000 . In the country's bicentennial year, the population was about 216,000,000 a) Assuming an exponential model, what was the growth rate of the United States through its bicentennial year? b) Is exponential growth a reasonable assumption? Why or why not?

The Rule of 70. The relationship between doubling time \(T\) and growth rate \(k\) is the basis of the Rule of \(70 .\) Since $$ T=\frac{\ln 2}{k}=\frac{0.693147}{k}=\frac{69.3147}{100 k} \approx \frac{70}{100 k} $$ we can estimate the length of time needed for a quantity to double by dividing the growth rate \(k\) (expressed as a percentage) into \(70 .\) Describe two situations where it would be preferable to use the Rule of 70 instead of the formula \(T=\ln (2) / k\). Explain why it would be acceptable to use this rule in these situations.

Quantity \(Q_{1}\) grows exponentially with a doubling time of 1 yr. Quantity \(Q_{2}\) grows exponentially with a doubling time of 2 yr. If the initial amounts of \(Q_{1}\) and \(Q_{2}\) are the same, how long will it take for \(Q_{1}\) to be twice the size of \(Q_{2} ?\)

We have now studied models for linear, quadratic, exponential, and logistic growth. In the real world, understanding which is the most appropriate type of model for a given situation is an important skill. For each situation, identify the most appropriate type of model and explain why you chose that model. List any restrictions you would place on the domain of the function. The growth in the length of Zachary's hair following a haircut

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