/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 The Technology Connection headin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Technology Connection heading indicates exercises designed to provide practice using a graphing calculator. Graph. \(x=8-y^{2}\)

Short Answer

Expert verified
Graph the functions \(y = \sqrt{8 - x}\) and \(y = -\sqrt{8 - x}\) for \(x \leq 8\) to visualize a sideways parabola.

Step by step solution

01

Rewrite the Equation

The given equation is in the form of an implicit function, \(x = 8 - y^2\). For graphing purposes, it can be useful to isolate \(y\). Rewrite it to \(y^2 = 8 - x\).
02

Solving for y

The equation \(y^2 = 8 - x\) can be solved in terms of \(y\). So, \(y = \pm \sqrt{8 - x}\). This indicates there are two functions to graph: \(y = \sqrt{8 - x}\) and \(y = -\sqrt{8 - x}\).
03

Determine the Domain

The expression under the square root, \(8 - x\), must be non-negative. Thus, \(8 - x \geq 0\), giving the domain \(x \leq 8\).
04

Plot the Graph

Using a graphing calculator, plot both functions \(y = \sqrt{8 - x}\) and \(y = -\sqrt{8 - x}\) for \(x \leq 8\). This will show a sideways parabola that opens to the left.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Calculators
Graphing calculators are powerful tools that help visualize mathematical expressions, making understanding complex equations easier. These calculators are not only used to solve equations but also to graph functions, which can bring to life the shapes and curves that mathematical formulas describe. When you input a function, a graphing calculator plots points for different values, connecting them to create a curve.

For example, consider the function from the exercise: with the implicit function rewritten as two separate equations, the graphing calculator can plot
  • \( y = \sqrt{8 - x} \)
  • \( y = -\sqrt{8 - x} \)
This produces a visual representation of the function in the shape of a sideways parabola. Graphing calculators also help identify key features of the graph, like intercepts and points of symmetry.

Using a graphing calculator gives students hands-on experience with data visualization, allowing them to easily tweak parameters and instantly see the impact. With these features, graphing calculators enhance understanding and provide immediate feedback.
Parabolas
A parabola is a U-shaped curve that can open upwards, downwards, or sideways. In mathematics, parabolas are described by quadratic equations. The standard form for a parabola that opens up or down is \( y = ax^2 + bx + c \), whereas the equation \( x = ay^2 + by + c \) represents a parabola opening sideways.

In our exercise, when we solve the given implicit function \( x = 8 - y^2 \), it represents a sideways parabola. The solution of this equation into two separate functions, \( y = \sqrt{8 - x} \) and \( y = -\sqrt{8 - x} \), creates a sideways opening parabola. The direction of this parabola is determined by the axis, which in this case, opens left towards negative x-values.

Understanding the shape and orientation of parabolas is crucial in fields such as physics, engineering, and architecture, where these curves describe trajectories and lens shapes, among other things. Parabolas are also key in analyzing quadratic relationships and optimizing solutions.
Domain and Range
The domain of a function is the set of all possible input values (usually \( x \)), while the range represents all possible output values (usually \( y \)). For many functions, particularly those involving square roots or divisions, determining the domain is crucial to avoid undefined operations.

In the case of the function described by \( x = 8 - y^2 \), after solving for \( y \), it's clear that the domain needs careful consideration. Since it involves a square root, the expression under the square root \( 8 - x \) must be greater than or equal to zero for real numbers. This gives the domain \( x \leq 8 \). In simpler terms, \( x \) can range from negative infinity to 8, including 8 itself.

The range is determined by the outputs of \( y \), which are \( y = \pm \sqrt{8 - x} \). Thus, the range matches the values produced by these expressions. By managing these limits, students can accurately plot the function on a graph and understand where breaks or twists might happen in a curve.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The population of Woodland is \(P\). After growing \(2 \%,\) the new population is \(N\). a) Assuming that \(N\) is directly proportional to \(P,\) find an equation of variation. b) Find \(N\) when \(P=200,000\). c) Find \(P\) when \(N=367,200\).

Solve for \(y\) in terms of \(x\), and determine if the resulting equation represents a function. $$ \left(3 y^{3 / 2}\right)^{2}=72 x $$

The Technology Connection heading indicates exercises designed to provide practice using a graphing calculator. Graph. \(9.6 x+4.2 y=-100\)

Rewrite each of the following as an equivalent expression using radical notation. $$ t^{-2 / 5} $$

The annual interest rate \(r,\) when compounded more than once a year, results in a slightly higher yearly interest rate; this is called the annual (or effective) yield and denoted as Y. For example, \$1000 deposited at 5\%, compounded monthly for 1 yr \((12\) months \(),\) will have a value of \(A=1000\left(1+\frac{0.05}{12}\right)^{12}=\$ 1051.16 .\) The interest earned is \(\$ 51.16 / \$ 1000,\) or \(0.05116,\) which is \(5.116 \%\) of the original deposit. Thus, we say this account has a yield of \(Y=0.05116,\) or \(5.116 \% .\) The formula for annual yield depends on the annual interest rate \(r\) and the compounding frequency \(n:\) \(Y=\left(1+\frac{r}{n}\right)^{n}-1.\) For Exercises 41-48, find the annual yield as a percentage, to two decimal places, given the annual interest rate and the compounding frequency. Annual interest rate of \(4.1 \%,\) compounded quarterly

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.