/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A function \(f\) takes a number ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A function \(f\) takes a number \(x,\) multiplies it by \(4,\) and adds 2 a) Write \(f\) as an equation. b) Graph \(f\).

Short Answer

Expert verified
a) \(f(x) = 4x + 2\); b) It's a straight line with slope 4, y-intercept 2.

Step by step solution

01

Understand the Function Description

The problem describes a function \(f\) that takes an input \(x\), multiplies it by 4, and adds 2 to the result. We need to translate this description into a mathematical form.
02

Write the Function as an Equation

Given the description of the function, we can express \(f(x)\) mathematically. The function equation can be written as: \(f(x) = 4x + 2\). This shows that for any input \(x\), you multiply by 4 and then add 2.
03

Identify the Elements for Graphing

The equation \(f(x) = 4x + 2\) represents a linear function. The slope (rate of change) of the line is 4, and the y-intercept (value of \(f(x)\) when \(x=0\)) is 2. These are essential elements for graphing the linear function.
04

Sketch the Graph

To graph \(f(x) = 4x + 2\), begin by plotting the y-intercept (0, 2) on the y-axis. Then use the slope to find another point; from the y-intercept, move 1 unit to the right (positive x-direction) and 4 units up (positive y-direction), leading you to the point (1, 6). Draw a line through these points to complete the graph of the function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Linear Equations
Graphing linear equations can initially seem intimidating, but it's quite simple once you understand the process. Linear equations describe a straight line when plotted on a graph. These equations are generally in the format of \( y = mx + b \), where \( m \) is the slope, and \( b \) is the y-intercept.

For the function \( f(x) = 4x + 2 \), this equation tells us how the function should be graphed. Here, \( f(x) \) is analogous to \( y \), making \( f(x) = 4x + 2 \) an equation in slope-intercept form, which we can use to graph the line.

To plot the graph:
  • Start with the y-intercept. The point where the line crosses the y-axis is the y-intercept. For this function, that point is (0, 2).
  • Next, use the slope to find the next point. The slope of 4 means for every 1 unit you move right on the x-axis, you move 4 units up on the y-axis. Starting at (0, 2), if you move 1 to the right, and 4 up, you'll land at the point (1, 6).
Once these points are plotted on the graph, draw a straight line through them to complete the linear equation's graph.
Slope and Intercept
Understanding slope and intercept is crucial for interpreting and graphing linear functions. The **slope** indicates the steepness or inclination of the line and is a measure of how much \( y \) changes for a one-unit increase in \( x \).

For our function \( f(x) = 4x + 2 \), the slope is 4. This means that for each additional unit of \( x \), the \( f(x) \) value increases by 4. The slope drives the direction and steepness of the line:
  • A positive slope, like 4, means the line inclines upwards as it moves from left to right.
  • A negative slope would indicate the opposite, with the line declining as you move right.
The **y-intercept** refers to where the line crosses the y-axis. In \( f(x) = 4x + 2 \), the y-intercept is 2. This is the value of \( f(x) \) when \( x = 0 \).

In slope-intercept form, \( y = mx + b \), \( b \) represents the y-intercept. Knowing the slope and y-intercept allows you to sketch the graph quickly and understand how the function behaves.
Function Representation
Function representation enables you to express mathematical relationships clearly. In this context, it takes a mathematical description and turns it into a recognizable form, making it easy to analyze and graph.

In our case, the function is represented as \( f(x) = 4x + 2 \). This representation highlights:
  • The dependence of \( f(x) \) on \( x \)
  • The operations applied to \( x \) (multiplication by 4 and addition of 2)
  • The resulting expression, which provides the output of the function for any input \( x \)
Having functions in this clear representation allows for:
  • Quick identification of the slope and y-intercept for graphing
  • Understanding how the input value \( x \) influences the output \( f(x) \)
Clear function representation is not just useful for graphing. It's essential for understanding all sorts of mathematical relationships and for solving real-world problems where these functions are applied.

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Most popular questions from this chapter

The annual interest rate \(r,\) when compounded more than once a year, results in a slightly higher yearly interest rate; this is called the annual (or effective) yield and denoted as Y. For example, \$1000 deposited at 5\%, compounded monthly for 1 yr \((12\) months \(),\) will have a value of \(A=1000\left(1+\frac{0.05}{12}\right)^{12}=\$ 1051.16 .\) The interest earned is \(\$ 51.16 / \$ 1000,\) or \(0.05116,\) which is \(5.116 \%\) of the original deposit. Thus, we say this account has a yield of \(Y=0.05116,\) or \(5.116 \% .\) The formula for annual yield depends on the annual interest rate \(r\) and the compounding frequency \(n:\) \(Y=\left(1+\frac{r}{n}\right)^{n}-1.\) For Exercises 41-48, find the annual yield as a percentage, to two decimal places, given the annual interest rate and the compounding frequency. Lena is considering two savings accounts: Western Bank offers \(4.5 \%,\) compounded annually, on saving accounts, while Commonwealth Savings offers \(4.43 \%,\) compounded monthly. a) Find the annual yield for both accounts. b) Which account has the higher annual yield?

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The surface area of a person whose mass is \(75 \mathrm{~kg}\) can be approximated by $$f(h)=0.144 h^{1 / 2}$$ where \(f(h)\) is measured in square meters and \(h\) is the person's height in centimeters. (Source: U.S. Oncology.) a) Find the approximate surface area of a person whose mass is \(75 \mathrm{~kg}\) and whose height is \(180 \mathrm{~cm}\). b) Find the approximate surface area of a person whose mass is \(75 \mathrm{~kg}\) and whose height is \(170 \mathrm{~cm}\). c) Graph the function \(f\) for \(0 \leq h \leq 200\).

The annual interest rate \(r,\) when compounded more than once a year, results in a slightly higher yearly interest rate; this is called the annual (or effective) yield and denoted as Y. For example, \$1000 deposited at 5\%, compounded monthly for 1 yr \((12\) months \(),\) will have a value of \(A=1000\left(1+\frac{0.05}{12}\right)^{12}=\$ 1051.16 .\) The interest earned is \(\$ 51.16 / \$ 1000,\) or \(0.05116,\) which is \(5.116 \%\) of the original deposit. Thus, we say this account has a yield of \(Y=0.05116,\) or \(5.116 \% .\) The formula for annual yield depends on the annual interest rate \(r\) and the compounding frequency \(n:\) \(Y=\left(1+\frac{r}{n}\right)^{n}-1.\) For Exercises 41-48, find the annual yield as a percentage, to two decimal places, given the annual interest rate and the compounding frequency. Annual interest rate of \(4.1 \%,\) compounded quarterly

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