/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 solve for \(x\) without using a ... [FREE SOLUTION] | 91Ó°ÊÓ

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solve for \(x\) without using a calculating utility. Use the natural logarithm anywhere that logarithms are needed. $$2 e^{3 x}=7$$

Short Answer

Expert verified
\( x = \frac{\ln\left(\frac{7}{2}\right)}{3} \)

Step by step solution

01

Isolate the Exponential Expression

Start with the given equation: \[ 2e^{3x} = 7 \]Divide both sides by 2 to isolate the exponential expression on one side:\[ e^{3x} = \frac{7}{2} \]
02

Apply the Natural Logarithm

Take the natural logarithm of both sides to remove the exponential expression:\[ \ln(e^{3x}) = \ln\left(\frac{7}{2}\right) \]
03

Simplify Using Logarithmic Identity

Use the identity \( \ln(e^a) = a \) to simplify the left side:\[ 3x = \ln\left(\frac{7}{2}\right) \]
04

Solve for x

Divide both sides by 3 to solve for \(x\):\[ x = \frac{\ln\left(\frac{7}{2}\right)}{3} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a specific type of logarithm that has the base \( e \). The constant \( e \) is approximately equal to 2.71828, and it appears in various mathematical contexts, especially when dealing with growth processes and exponential functions. The natural logarithm is particularly useful when solving exponential equations because it effectively "undoes" the exponential nature of functions that use \( e \) as a base.

The natural logarithm has a few key properties:
  • \( \ln(1) = 0 \) because \( e^0 = 1 \).
  • \( \ln(e) = 1 \) because the base \( e \) raised to the power of 1 equals \( e \).
Understanding these properties is crucial when solving problems involving exponential equations. When you encounter an equation like \( e^{3x} = \frac{7}{2} \), using the natural logarithm allows you to convert the exponential expression into a simpler algebraic form that you can solve more easily. Remember, taking the natural logarithm of both sides of an equation is a powerful method for tackling exponential equations.
Logarithmic identities
Logarithmic identities are essential tools that help simplify and solve equations involving logarithms. They express rules that are consistently true for logarithms, regardless of base. However, when dealing with natural logs, we most often encounter these simplified rules for the base \( e \).Let's cover some fundamental logarithmic identities:
  • Power Rule: \( \ln(a^b) = b \ln(a) \). This identity indicates that the logarithm of a power turns the exponent into a coefficient.
  • Product Rule: \( \ln(ab) = \ln(a) + \ln(b) \). This identity means that the logarithm of a product is the sum of the logarithms.
  • Quotient Rule: \( \ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b) \). This rule shows that the logarithm of a quotient results in the difference of the logarithms.
In exponential equations, these identities help break down and manipulate expressions more cleanly. In the original problem, the identity \( \ln(e^a) = a \) was key to simplifying the left side of the equation. Familiarity with these identities makes it easier to both comprehend and solve logarithmic and exponential equations.
Solving Exponential Equations
Solving exponential equations involves finding unknown variable values in equations where the variable is an exponent. These equations frequently appear in contexts such as growth models, financial calculations, and decay processes.Here's a straightforward process to solve exponential equations like \( e^{3x} = \frac{7}{2} \):1. **Isolate the Exponential Part:**
Start by making the exponential term the subject of the equation so that you can manage and work with it more easily. For example, divide both sides as needed to isolate the exponential expression.2. **Apply the Natural Logarithm:**
Taking the natural logarithm of both sides allows you to remove the exponential nature. This transformation provides a simpler and more linear form, turning exponents into simple coefficients.3. **Simplify Using Identities:**
Use applicable logarithmic identities to further simplify the equation where possible. For instance, the identity \( \ln(e^a) = a \) simplifies the natural log form significantly.4. **Solve for the Variable:**
Finally, solve the resulting algebraic equation for the unknown variable using basic algebraic manipulations such as division or multiplication to isolate the variable.By following these steps, you gain a systematic approach to solving more complex exponential equations which could otherwise seem daunting at first glance.

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Most popular questions from this chapter

Determine whether the function \(f\) is one-to-one by examining the sign of \(f^{\prime}(x)\). (a) \(f(x)=x^{3}+3 x^{2}-8\) (b) \(f(x)=x^{5}+8 x^{3}+2 x-1\) (c) \(f(x)=\frac{x}{x+1}\)

Find the limit. $$\lim _{x \rightarrow+\infty}(1-3 / x)^{x}$$

Two curves are said to be orthogonal if their tangent lines are perpendicular at each point of intersection, and two families of curves are said to be orthogonal trajectories of one another if each member of one family is orthogonal to each member of the other family. The accompanying figure shows some typical members of the families of circles \(x^{2}+(y-c)^{2}=c^{2}\) (black curves) and \((x-k)^{2}+y^{2}=k^{2}\) (gray curves). Show that these families are orthogonal trajectories of one another. IHint: For the tangent lines to be perpendicular at a point of intersection, the slopes of those tangent lines must be negative reciprocals of one another. \(]\) GRAPH CANT COPY

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