/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Find the limit. $$\lim _{x \ri... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limit. $$\lim _{x \rightarrow+\infty}(1-3 / x)^{x}$$

Short Answer

Expert verified
The limit is \( e^{-3} \).

Step by step solution

01

Identify the Expression Form

The expression given is \( \lim_{x \rightarrow +\infty} (1-\frac{3}{x})^x \). This is of the form \( \lim_{x \rightarrow +\infty} (1 + \frac{a}{x})^x \), where \( a = -3 \). This form is suitable for applying the exponential limit rule, which states that \( \lim_{x \to \infty} \left( 1 + \frac{a}{x} \right)^x = e^a \).
02

Apply the Exponential Limit Rule

Using the rule \( \lim_{x \to \infty} \left( 1 + \frac{a}{x} \right)^x = e^a \), substitute \( a = -3 \) into the formula. Thus, \( \lim_{x \to \infty} \left( 1 - \frac{3}{x} \right)^x = e^{-3} \).
03

Calculate the Limit

Since applying the rule directly gives us the answer, evaluate \( e^{-3} \). Hence, the limit \( \lim_{x \rightarrow +\infty} (1-\frac{3}{x})^x = e^{-3} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Limit Rule
The exponential limit rule is a vital concept in calculus, especially when evaluating limits of expressions of the form \( \lim_{x \to \infty} \left( 1 + \frac{a}{x} \right)^x \). This rule allows us to simplify complex-looking limits into something more manageable. In the provided exercise, the expression \( (1 - \frac{3}{x})^x \) fits this form, with \( a = -3 \).

The exponential limit rule asserts that such expressions tend toward \( e^a \) as \( x \) approaches infinity. This rule relies on the behavior of the base of natural logarithms, Euler's number \( e \). Essentially, as the term \( \frac{a}{x} \) becomes very small when \( x \) is large, the entire expression acts like a natural exponential function, where the limit equates to \( e^a \).
  • Recognize the form as \( \left( 1 + \frac{a}{x} \right)^x \)
  • Apply the rule: \( \lim_{x \to \infty} \left( 1 + \frac{a}{x} \right)^x = e^a \)
  • For \( a = -3 \), the result is \( e^{-3} \)
Infinite Limits
Infinite limits consider the behavior of functions as the input grows without bound. In the case of exponential limits, we're particularly focused on what happens to expressions as \( x \) approaches infinity. It's a way to understand long-term behavior in mathematical functions.

For the expression \( \lim_{x \rightarrow +\infty} (1-\frac{3}{x})^x \), as \( x \) becomes larger and larger, \( -\frac{3}{x} \) tends to zero. However, due to the entire expression burgeoning in an exponential fashion, the limit converges to a finite number. In our problem, this number is \( e^{-3} \).
  • Consider the effect of \( x \to \infty \) on each component of the function.
  • Interpret \( a/x \) where it diminishes as \( x \) swells.
  • Notice the transformation into a natural exponent, yielding a finite limit.
Euler's Number (e)
Euler's number, \( e \), is an essential mathematical constant, approximately equal to 2.71828. It's especially important in calculus and complex analysis because of its unique properties.

The number \( e \) arises naturally in discussions about growth and compounding processes. This property makes it the base of natural logarithms and the cornerstone of exponential functions. In the context of the exponential limit rule, \( e \) signifies the limit of \( \left( 1 + \frac{1}{n} \right)^n \) as \( n \) approaches infinity. Consequently, \( e^a \) becomes a dominant solution to problems involving rates of growth or decay.
  • Recognized for its approximation: 2.71828.
  • Serves as the base for natural logarithms.
  • Fundamental in understanding growth, decay, and complex number systems.

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Most popular questions from this chapter

There is a myth that circulates among beginning calculus students which states that all indeterminate forms of types \(0^{0}, \infty^{0},\) and \(1^{*}\) have value 1 because "anything to the zero power is \(1^{\prime \prime}\) and \(" 1\) to any power is \(1 . "\) The fallacy is that \(0^{0}, \infty^{0},\) and \(1^{\times x}\) are not powers of numbers, but rather descriptions of limits. The following examples, which were transmitted to me by Prof. Jack Staib of Drexel University, show that such indeterminate forms can have any positive real value: (a) \(\lim _{x \rightarrow 0^{+}}\left[x^{(\ln a) /(1+\ln x)}\right]=0^{0}=a\) (b) \(\lim _{x \rightarrow+\infty}\left[x^{(\ln a) /(1+\ln x)}\right]=\infty^{0}=a\) (c) \(\lim _{x \rightarrow 0}\left[(x+1)^{(\ln a) / x}\right]=1^{x}=a\) Prove these results.

Make a conjecture about the limit by graphing the function involved with a graphing utility; then check your conjecture using L'Hôpital's rule. $$\lim _{x \rightarrow(1 / 2) \pi^{-}} \frac{4 \tan x}{1+\sec x}$$

Find the limit. $$\lim _{x \rightarrow+\infty}[\cos (2 / x)]^{x^{2}}$$

On the Richter scale. the magnitude \(M\) of an earthquake is related to the released energy \(E\) in joules \((\mathrm{J})\) by the equation \(\log E=4.4+1.5 M\) (a) Find the energy \(E\) of the 1906 San Francisco earthquake that registered \(M=8.2\) on the Richter scale. (b) If the released energy of one earthquake is 10 times that of another. how much greater is its magnitude on the Richter scale?

The perceived loudness \(\beta\) of a sound in decibels (dB) is related to its intensity \(l\) in watts/square meter \(\left(\mathrm{W} / \mathrm{m}^{2}\right)\) by the equation $$\beta=10 \log \left(1 / I_{0}\right)$$ where \(I_{0}=10^{-12} \mathrm{W} / \mathrm{m}^{2} .\) Damage to the average ear occurs at 90 dB or greater. Find the decibel level of each of the following sounds and state whether it will cause ear damage. $$\begin{array}{lclcl} & \text { SOUND } & I \\ \text { (a) } & \text { Jet aircraft (from 500 ft) } & 1.0 \times 10^{2} \mathrm{W} / \mathrm{m}^{2} \\\ \text { (b) } & \text { Amplified rock music } & 1.0 \mathrm{W} / \mathrm{m}^{2} \\ \text { (c) } & \text { Garbage disposal } & 1.0 \times 10^{-4} \mathrm{W} / \mathrm{m}^{2} \\ \text { (d) } & \text { TV (mid volume from 10 } \mathrm{ft} \text { ) } & 3.2 \times 10^{-5} \mathrm{W} / \mathrm{m}^{2}\end{array}$$

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