Chapter 11: Problem 32
Find the coordinates of the focus of the parabola that is the intersection of \(z=x^{2} / 4+y^{2} / 9\) with \(x=4\).
Short Answer
Expert verified
The focus is at the point (4, 0, 25/4).
Step by step solution
01
Substitute x-value into parabola equation
The equation of the parabola is given as \( z = \frac{x^2}{4} + \frac{y^2}{9} \). We substitute \( x = 4 \) into this equation to find the relationship between \( z \) and \( y \) when \( x = 4 \). Thus, we have:\[ z = \frac{4^2}{4} + \frac{y^2}{9} = 4 + \frac{y^2}{9} \]
02
Identify the shape and orientation
From the above equation, we have \( z = 4 + \frac{y^2}{9} \). This represents a parabola that opens in the \( z \,\) direction, with \( y^2 \) being present, indicating the standard form \( z = ay^2 + c \). Here, \( a = \frac{1}{9} \) and \( c = 4 \).
03
Determine the vertex of the parabola
The vertex of the parabola \( z = 4 + \frac{y^2}{9} \) is at the point where \( y = 0 \). Substituting \( y = 0 \) into the equation gives \( z = 4 \). Thus, the vertex is at the point (4, 0, 4).
04
Calculate the focus of the parabola
For a parabola in the form \( z = ay^2 + C \), the focus is given by \( (p, 0, C + \frac{1}{4a}) \) where \( p = 4 \), \( C = 4 \), and \( a = \frac{1}{9} \). Plugging in these values gives:\[ (4, 0, 4 + \frac{1}{4(\frac{1}{9})}) = (4, 0, 4 + \frac{9}{4}) = (4, 0, \frac{25}{4}) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a crucial element in understanding its geometry. It represents the point where the parabola changes direction. For a standard quadratic equation, the vertex can be found by locating the minimum or maximum point.
In our exercise, we are dealing with a parabolic shape described by the equation \( z = 4 + \frac{y^2}{9} \). When analyzing this equation, we observe that the vertex occurs when \( y = 0 \). Therefore, substituting \( y = 0 \) into the equation results in \( z = 4 \). Hence, the vertex of the parabola within the context of this spatial setup is (4, 0, 4).
In our exercise, we are dealing with a parabolic shape described by the equation \( z = 4 + \frac{y^2}{9} \). When analyzing this equation, we observe that the vertex occurs when \( y = 0 \). Therefore, substituting \( y = 0 \) into the equation results in \( z = 4 \). Hence, the vertex of the parabola within the context of this spatial setup is (4, 0, 4).
- This point denotes where the curve starts expanding or contracting.
- It's the "highest" or "lowest" point for parabola shapes, dependent on the opening direction.
Equation of a Parabola
Understanding the equation of a parabola is essential for deducing its properties and behavior. Generally, a parabola's equation in its standard form looks like \( z = ay^2 + c \) for curves situated in 3D space, as seen in our exercise.
Here, the equation \( z = \frac{x^2}{4} + \frac{y^2}{9} \) describes the relation between \( x \), \( y \), and \( z \) in a 3-dimensional space. By setting \( x = 4 \), the equation simplifies to \( z = 4 + \frac{y^2}{9} \), which expresses a parabola with:
Here, the equation \( z = \frac{x^2}{4} + \frac{y^2}{9} \) describes the relation between \( x \), \( y \), and \( z \) in a 3-dimensional space. By setting \( x = 4 \), the equation simplifies to \( z = 4 + \frac{y^2}{9} \), which expresses a parabola with:
- Coefficient \( a = \frac{1}{9} \) indicating the "spread" or "narrowness".
- Vertical shift \( c = 4 \), showing a displacement along the \( z \)-axis.
Geometry of Space Curves
Analyzing the geometry of space curves, especially parabolas, gives insight into their spatial behavior. In three-dimensional space, parabolas can take on different orientations and directions compared to the simple 2D perspective.
In this exercise, the parabola is defined by intersection equations, illustrating a path defined in the \( z \)-component based on \( x \) and \( y \). Setting \( x = 4 \) transforms it into a simpler 2D curve along the \( y \) and \( z \)-axes:
In this exercise, the parabola is defined by intersection equations, illustrating a path defined in the \( z \)-component based on \( x \) and \( y \). Setting \( x = 4 \) transforms it into a simpler 2D curve along the \( y \) and \( z \)-axes:
- This demonstrates a concept of space curves, where each variable contributes to defining the path.
- Such configurations are essential in fields like physics, where trajectories and surfaces are modeled.