Chapter 11: Problem 14
. If \(\mathbf{u}+\mathbf{v}\) is orthogonal to \(\mathbf{u}-\mathbf{v},\) what can you say about the relative magnitudes of \(\mathbf{u}\) and \(\mathbf{v} ?\)
Short Answer
Expert verified
The vectors \(\mathbf{u}\) and \(\mathbf{v}\) have the same magnitude.
Step by step solution
01
Use Orthogonality Definition
Two vectors, \(\mathbf{a}\) and \(\mathbf{b}\), are orthogonal if their dot product is zero. We are given that \(\mathbf{u} + \mathbf{v}\) is orthogonal to \(\mathbf{u} - \mathbf{v}\). Thus, the dot product of these vectors must be zero: \((\mathbf{u} + \mathbf{v}) \cdot (\mathbf{u} - \mathbf{v}) = 0.\)
02
Expand the Dot Product
Expand the dot product expression: \((\mathbf{u} + \mathbf{v}) \cdot (\mathbf{u} - \mathbf{v}) = \mathbf{u} \cdot \mathbf{u} - \mathbf{u} \cdot \mathbf{v} + \mathbf{v} \cdot \mathbf{u} - \mathbf{v} \cdot \mathbf{v}.\) This simplifies to: \(\mathbf{u} \cdot \mathbf{u} - \mathbf{v} \cdot \mathbf{v}.\)
03
Set the Expanded Expression to Zero
Since the expression is zero from orthogonality, set the equation \(\mathbf{u} \cdot \mathbf{u} - \mathbf{v} \cdot \mathbf{v} = 0\). This implies that \(\Vert \mathbf{u} \Vert^2 = \Vert \mathbf{v} \Vert^2\), where \(\Vert \bullet \Vert\) denotes the magnitude of a vector.
04
Conclude the Relationship Between Magnitudes
Taking the square root of both sides, we find that \(\Vert \mathbf{u} \Vert = \Vert \mathbf{v} \Vert\). Therefore, the vectors \(\mathbf{u}\) and \(\mathbf{v}\) have the same magnitude.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
The **dot product** is a fundamental operation in the realm of vectors, serving as a bridge between algebra and geometry. It is especially useful in determining the relationship between two vectors. The dot product of two vectors gives a scalar and is defined as the product of the magnitudes of the vectors and the cosine of the angle between them. Mathematically, for vectors \( \mathbf{a} = (a_1, a_2, a_3) \) and \( \mathbf{b} = (b_1, b_2, b_3) \), the dot product is computed as:
- \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \)
- If the dot product equals zero, the vectors are orthogonal (perpendicular).
- The dot product can also give information about the angle between vectors.
Vector Magnitude
The **magnitude** of a vector offers information about its size or length. For a vector \( \mathbf{v} = (v_1, v_2, v_3) \), we calculate its magnitude using the formula:
- \( \Vert \mathbf{v} \Vert = \sqrt{v_1^2 + v_2^2 + v_3^2} \)
Orthogonality Condition
The **orthogonality condition** fundamentally states that two vectors are orthogonal if their dot product equals zero. This condition is fundamental in vector analysis and provides a method for determining the perpendicularity of vectors without directly measuring angles. In geometric terms, orthogonal vectors form right angles with each other.In the exercise, it is given that \( \mathbf{u} + \mathbf{v} \) is orthogonal to \( \mathbf{u} - \mathbf{v} \), making their dot product naturally zero. This orthogonality condition helps us find a relationship between their magnitudes:
- The equation \( \mathbf{u} \cdot \mathbf{u} - \mathbf{v} \cdot \mathbf{v} = 0 \) simplifies to \( \Vert \mathbf{u} \Vert ^2 = \Vert \mathbf{v} \Vert ^2 \).
- This means that \( \Vert \mathbf{u} \Vert = \Vert \mathbf{v} \Vert \), establishing that both vectors have equal magnitudes.