/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Sketch a graph of the equation. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch a graph of the equation. $$y=\frac{1}{3} x-1$$

Short Answer

Expert verified
The graph of the equation \(y = \frac{1}{3} x - 1\) is a straight line that crosses the y-axis at (0,-1) and goes upwards with a slope of \(\frac{1}{3}\).

Step by step solution

01

Identify the y-intercept

The y-intercept is the value of y when x = 0. In this case, the equation is \(y = \frac{1}{3}*0 - 1\), which simplifies to \(y = -1\). So, the line crosses the y-axis at the point (0,-1).
02

Determine the slope

The slope of a line is determined by the coefficient of x. In this case, it is \(\frac{1}{3}\). The slope tells us that for every 3 units we move to the right on the x-axis, we move up by 1 unit on the y-axis. This will be crucial in drawing the graph.
03

Plot the y-intercept and use the slope to plot more points

Start by plotting the y-intercept, which is (0, -1). From this point, move 3 units to the right along the x-axis and 1 unit up along the y-axis to plot the next point. Connect these points with a straight line. This line is the graph of the equation \(y = \frac{1}{3} x - 1\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Y-Intercept
When graphing linear equations, one of the key components to identify is the y-intercept. This is the point where the line crosses the y-axis. In simpler terms, it's where the line 'intercepts' the y-axis. To find the y-intercept, set the x-value to zero and solve for y based on your equation. For example, with the equation \( y = \frac{1}{3}x - 1 \) when x is 0, \( y = -1 \). Thus, the y-intercept is (0, -1). The importance of understanding the y-intercept cannot be overstated; it serves as a starting point for plotting the graph of the line.

When it comes to the equation provided, the y-intercept is particularly important because it is also where the plotting process begins. From the y-intercept, you use the slope to determine the direction and steepness of the line as you plot additional points.
Determining the Slope
The slope of a line measures its steepness, typically represented by the letter \( m \). It's calculated as the rise over the run – think of it as how much you go up or down (rise) for a given distance to the right or left (run). For the equation \( y = \frac{1}{3}x - 1 \), the slope is \( \frac{1}{3} \) which means for every 3 units you move horizontally to the right, you move 1 unit vertically upwards.

This concept is crucial for not only plotting the line but also understanding the rate of change the equation represents. A positive slope means the line is increasing as you move from left to right, whereas a negative slope indicates a decreasing line. In our case, the positive \( \frac{1}{3} \) slope tells us the line will slant upwards as we move along the x-axis.
Plotting Points to Graph the Equation
With the y-intercept and slope in hand, the next step in graphing a linear equation is plotting points. Starting at the y-intercept, use the slope to find other points on the line. In our example, we begin at the y-intercept which is (0, -1), then move 3 units to the right and 1 unit up to plot the next point at (3, 0). Repeat this process to find more points if needed.

You can also plot points starting from any known point on the line by moving in the opposite direction based on the slope. For example, you could move 3 units to the left and 1 unit down from the known point. The key is consistency in following the slope to ensure all points line up straight, confirming the 'linear' part of 'linear equation'.
Utilizing Slope-Intercept Form
The slope-intercept form of a line's equation is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. It's a straightforward way to graph linear equations because it gives you the slope and y-intercept directly. For the given example, the slope-intercept form is already presented as \( y = \frac{1}{3}x - 1 \), indicating a slope (m) of \( \frac{1}{3} \) and a y-intercept (b) of -1.

This form is especially user-friendly for students new to graphing, as it avoids the need for additional calculations to start the plotting process. It's also a useful form for quickly understanding how changes in the equation will affect the graph, such as how the line will shift if the y-intercept changes or how the steepness will alter with different slope values.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the distance between the point and line, or between the lines, using the formula for the distance between the point \(\left(x_{1}, y_{1}\right)\) and the line \(A x+B y+\) \(C=0 .\) Line: \(3 x-4 y=1\) Line: \(3 x-4 y=10\)

Find the domain of the function. $$g(x)=\frac{2}{1-\cos x}$$

Reimbursed Expenses A company reimburses its sales representatives \(\$ 150\) per day for lodging and meals plus \(34 \mathrm{c}\) per mile driven. Write a linear equation giving the daily cost \(C\) to the company in terms of \(x\), the number of miles driven. How much does it cost the company if a sales representative drives 137 miles on a given day?

Hooke's Law Hooke's Law states that the force \(F\) required to compress or stretch a spring (within its elastic limits) is proportional to the distance \(d\) that the spring is compressed or stretched from its original length. That is, \(F=k d\), where \(k\) is a measure of the stiffness of the spring and is called the spring constant. The table shows the elongation \(d\) in centimeters of a spring when a force of \(F\) newtons is applied. $$ \begin{array}{|c|c|c|c|c|c|} \hline \boldsymbol{F} & 20 & 40 & 60 & 80 & 100 \\ \hline \boldsymbol{d} & 1.4 & 2.5 & 4.0 & 5.3 & 6.6 \\ \hline \end{array} $$ (a) Use the regression capabilities of a graphing utility to find a linear model for the data. (b) Use a graphing utility to plot the data and graph the model. How well does the model fit the data? Explain your reasoning. (c) Use the model to estimate the elongation of the spring when a force of 55 newtons is applied.

Prove that if the slopes of two nonvertical lines are negative reciprocals of each other, then the lines are perpendicular. Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.