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Find the distance between the point and line, or between the lines, using the formula for the distance between the point \(\left(x_{1}, y_{1}\right)\) and the line \(A x+B y+\) \(C=0 .\) Line: \(3 x-4 y=1\) Line: \(3 x-4 y=10\)

Short Answer

Expert verified
The distance between the lines \(3x - 4y = 1\) and \(3x - 4y = 10\) is 2.2 units.

Step by step solution

01

Identify the line equations

The given lines are \(3x - 4y = 1\) and \(3x - 4y = 10\). The generic form of a line equation is \(Ax + By + C = 0\). Identifying the coefficients, we have \(A=3\), \(B=-4\), \(C1=1\), and \(C2=-10\) for the first and second line respectively.
02

Write down the distance formula

From geometry, the formula to find the distance 'd' between two parallel lines defined as \(Ax + By + C1 = 0\) and \(Ax + By + C2 = 0\) is \[d = \frac{{|C2 - C1|}}{{\sqrt{A^2 + B^2}}}\]
03

Substitute values into the formula

Substitute the identified values into the formula: \[d = \frac{{|-10 - 1|}}{{\sqrt{3^2 + (-4)^2}}}\]
04

Simplify the equation

Solving the equation, we have: \[d = \frac{{11}}{{\sqrt{9 + 16}}}\] = \[d = \frac{{11}}{{\sqrt{25}}}\] = \[d = \frac{{11}}{{5}}}\] = 2.2

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Line Equations
Understanding line equations is essential for studying the relationships between lines, particularly when determining their distance apart. The equation of a line in two-dimensional space can take several forms, but a common one is the standard form, expressed as Ax + By + C = 0. In this expression, A and B denote the coefficients that dictate the slope of the line, while C represents the line's intercept on the y-axis when x = 0.

When solving problems involving the distance between two parallel lines, it is critical to notice that these lines will have identical A and B coefficients, but different C values. This is because parallel lines have the same slope but are shifted vertically or horizontally. By analyzing the standard form equations of our given lines, we confirm they are parallel due to the same A and B values. Thus, we have the foundation to apply the distance formula correctly.
Geometry
Geometry, the branch of mathematics concerning shapes and their properties, is pivotal when learning about lines and distances. We employ geometric principles to comprehend the properties of parallel lines and how they behave in space. Notably, parallel lines maintain a constant distance between them and never intersect, a fact that underpins the process of finding the distance between them.

In practice, visualizing the scenario can greatly enhance understanding. Imagine two parallel lines like train tracks extending into the horizon. Despite the perspective might make them appear to converge, they actually run alongside each other at a consistent separation. This constancy allows us to define the distance formula for parallel lines, a straightforward application of geometry, to resolve real-world and theoretical problems.
Distance Formula
The distance formula possesses the key to unlock the gap between two parallel lines. Drawing from geometry, the formula is given by d = |C2 - C1| / sqrt(A^2 + B^2), where the numerator represents the absolute difference between the respective C values of the two lines, and the denominator represents the square root of the sum of the squares of coefficients A and B.

Applying this formula to our initial problem, we substitute the coefficients derived from the line equations, diligently following the steps to reveal the answer. This methodical approach not only ensures accuracy but also builds a deeper appreciation for how algebra and geometry intersect. The distance formula is a beautiful expression of this union, showcasing how the abstract symbolism of algebra corresponds to the tangible concepts of geometric shapes and distances.

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Most popular questions from this chapter

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