Chapter 1: Problem 16
Simplify the quantities using \(m(z)=z^{2}\). $$m(z+h)-m(z)$$
Short Answer
Expert verified
The simplified form is \(2zh + h^2\).
Step by step solution
01
Understand the Function
The function given is \(m(z) = z^2\). This means that it takes any input \(z\), and outputs \(z\) squared. This function will be used to transform both \(z+h\) and \(z\) separately.
02
Apply the Function to \(z+h\)
We need to find the function's output when the input is \(z+h\). Using our function \(m(z) = z^2\), we calculate \(m(z+h) = (z+h)^2\).
03
Expand \((z+h)^2\)
Apply the formula for the square of a binomial: \((z+h)^2 = z^2 + 2zh + h^2\).
04
Apply the Function to \(z\)
Now, compute \(m(z) = z^2\). This is simply \(z^2\) since it's directly from the function definition \(m(z) = z^2\).
05
Subtract \(m(z)\) from \(m(z+h)\)
Substitute the expressions obtained: \(m(z+h) - m(z) = (z^2 + 2zh + h^2) - z^2\).
06
Simplify the Expression
Combine like terms to simplify: \(z^2 + 2zh + h^2 - z^2 = 2zh + h^2\). The \(z^2\) terms cancel out.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Simplification
Function simplification is a key process in calculus that involves reducing complex expressions into a simpler, more manageable form. The goal is to make calculations easier and to identify patterns or behaviors of a function. In this exercise, we worked with the function \( m(z) = z^2 \). By applying this function to different expressions like \( z+h \), we expand and then simplify the resulting expressions.
To simplify \( m(z+h) - m(z) \), we did the following:
To simplify \( m(z+h) - m(z) \), we did the following:
- Calculated \( m(z+h) = (z+h)^2 \) and then expanded it using the distributive property.
- Found \( m(z) \) which is simply \( z^2 \).
- Subtracted the two expressions: \( (z^2 + 2zh + h^2) - z^2 \).
- Cancelled out the \( z^2 \) terms to get \( 2zh + h^2 \).
Binomial Expansion
Binomial expansion is a technique used to expand expressions that are raised to a power, typically seen in the form \((a + b)^n\). In our exercise, we encountered this when transforming \((z+h)^2\).The general formula for expanding a binomial is
- \((a + b)^2 = a^2 + 2ab + b^2\)
- \((z+h)^2 = z^2 + 2zh + h^2\)
Difference Quotient
The difference quotient is a crucial concept in calculus, often used to find the derivative of a function. It represents the average rate of change of the function over a small interval and is defined as:
- \( \frac{f(x+h) - f(x)}{h} \)