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Find a linear function that generates the values in Table 1.3 $$\begin{array}{c|r|r|r|r|r} \hline x & 5.2 & 5.3 & 5.4 & 5.5 & 5.6 \\ \hline y & 27.8 & 29.2 & 30.6 & 32.0 & 33.4 \\ \hline \end{array}$$

Short Answer

Expert verified
The linear function is \(y = 14x - 45\).

Step by step solution

01

Identify the Variables

We will consider the given values of \(x\) and \(y\) from the table. Let the function be of the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
02

Calculate the Slope (m)

The slope \(m\) of a linear function is given by the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Let's use the points \((5.2, 27.8)\) and \((5.3, 29.2)\) for these calculations:\[m = \frac{29.2 - 27.8}{5.3 - 5.2} = \frac{1.4}{0.1} = 14\]
03

Calculate the Y-intercept (b)

Now, use one of the points to find \(b\). Let's use the point \((5.2, 27.8)\) in the equation \(y = mx + b\):\[27.8 = 14(5.2) + b\]\[27.8 = 72.8 + b\]\[b = 27.8 - 72.8 = -45\]
04

Write the Linear Function

Now that we know \(m = 14\) and \(b = -45\), we can write the linear function:\[y = 14x - 45\]
05

Verify the Function with Other Points

To ensure the function is correct, substitute other \(x\) values from the table back into the function and check if they provide the given \(y\) values. For example, for \(x = 5.4\):\[y = 14(5.4) - 45 = 30.6\]Since this matches the table, our function is verified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope
The slope of a linear function is a crucial concept in understanding how the function behaves. It tells us how much the value of the function (or the output "y") will change with each one-unit increase in "x" (the input). In simpler terms, if you think of a graph of the function as a hill, the slope represents how steep the hill is.

To find the slope, we can use the formula:
  • \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Here, \(m\) is the slope, \(x_1\) and \(y_1\) are the coordinates of one point on the line, and \(x_2\) and \(y_2\) are the coordinates of another point.

In our example, using the points \((5.2, 27.8)\) and \((5.3, 29.2)\), we calculated the slope as \(14\). This tells us that for each increase of 1 in \(x\), \(y\) increases by 14. A steep, positive slope indicates a sharp increase in values.
Y-intercept
The y-intercept is the point where the line of a linear function crosses the y-axis. It's an essential part of the linear function, represented by the \(b\) in the equation \(y = mx + b\). This tells you the value of \(y\) when \(x = 0\).

To find the y-intercept, you can rearrange the linear equation to solve for \(b\). Using one of the points, like \((5.2, 27.8)\), and our previously found slope of \(14\), we substituted it into the equation:
  • \(27.8 = 14(5.2) + b\)
Solving this gives us \(b = -45\). Thus, the y-intercept of our function is \(-45\), meaning that if the function line extended to where \(x = 0\), \(y\) would be \(-45\).

Remember, the y-intercept can sometimes be positive, negative, or zero, depending on the line's position.
Linear Equations
Linear equations describe straight lines on a graph and are in the form \(y = mx + b\). This is a simple yet powerful equation that models relationships in various fields, from science to economics.

Let’s break it down:
  • \(m\): The slope, showing how much \(y\) changes as \(x\) changes.
  • \(b\): The y-intercept, indicating the function's starting point at \(x = 0\).
In our scenario, the linear equation generated from the table's data is \(y = 14x - 45\). Each part plays a role in depicting how x and y are related.

Understanding linear equations is fundamental, as they help solve real-world problems by predicting outcomes and patterns when variables change linearly.
Function Verification
Verifying that a linear function accurately represents the data is as important as finding the function itself. This step ensures that calculations are correct and the function truly models the data.

Function verification involves plugging in other known values of \(x\) from the data table into the derived function and checking if it yields the corresponding \(y\). Using our function \(y = 14x - 45\), we checked the point where \(x = 5.4\) and found that \(y = 30.6\), which matches the given table value.
  • Substitute \(x\) into the equation.
  • Calculate \(y\).
  • Verify if calculated \(y\) matches the table.
If all other original data points verify, it's likely that the linear function is correct. It serves as a double-check, reinforcing the function's reliability before using it for predictions or analysis.

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Most popular questions from this chapter

If \(g(x)=\ln (a x+2),\) where \(a \neq 0,\) what is the effect of increasing \(a\) on (a) The \(y\) -intercept? (b) The \(x\) -intercept?

A baseball hit at an angle of \(\theta\) to the horizontal with initial velocity \(v_{0}\) has horizontal range, \(R,\) given by $$ R=\frac{v_{0}^{2}}{g} \sin (2 \theta) $$ Here \(g\) is the acceleration due to gravity. Sketch \(R\) as a function of \(\theta\) for \(0 \leq \theta \leq \pi / 2 .\) What angle gives the maximum range? What is the maximum range?

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Which of the following functions has its domain identical with its range? (a) \(\quad f(x)=x^{2}\) (b) \(\quad g(x)=\sqrt{x}\) (c) \(h(x)=x^{3}\) (d) \(\quad i(x)=|x|\)

For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, \(d(t),\) in meters, where \(t\) is measured in hours since midnight, is $$ d(t)=5+4.6 \sin (0.5 t) $$ (a) What is the period of the tides in hours? (b) If the boat leaves the bay at midday, what is the latest time it can return before the water becomes too shallow?

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