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Find the general solution to the differential equation. $$\frac{d y}{d x}=\frac{1}{x}, \text { where } x>0$$

Short Answer

Expert verified
The general solution is \( y = \ln|x| + C \).

Step by step solution

01

Write the Differential Equation in Standard Form

The given differential equation is \( \frac{dy}{dx} = \frac{1}{x} \). In this form, \( \frac{dy}{dx} \) is already isolated which represents the derivative of \( y \) with respect to \( x \).
02

Separate the Variables

To solve the differential equation, we can use the method of separation of variables. Rewrite the equation as \( dy = \frac{1}{x} \, dx \).
03

Integrate Both Sides

Integrate both sides of the equation to find \( y \). - The integral of \( dy \) is \( y \).- The integral of \( \frac{1}{x} \, dx \) is \( \ln|x| \). Thus, we have: \[ y = \ln|x| + C \] where \( C \) is an integration constant.
04

State the General Solution

The general solution to the differential equation \( \frac{dy}{dx} = \frac{1}{x} \) is given by \[ y = \ln|x| + C \] where \( C \) is an arbitrary constant that can take any real value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Method of Separation of Variables
The method of separation of variables is a straightforward technique to solve differential equations, enabling us to find solutions by separating the variables on opposite sides of the equation. In the context of a differential equation, this method involves rewriting the equation such that all the terms involving one variable (say, \( y \)) appear on one side and all the terms involving the other variable (say, \( x \)) reside on the other.

In our given exercise, the differential equation is \( \frac{dy}{dx} = \frac{1}{x} \). By rearranging the terms, we manage to isolate the differential components as \( dy = \frac{1}{x} \, dx \). This way, the variables \( y \) and \( x \) are cleanly separated, allowing us to integrate each side independently.

This approach is particularly friendly because:
  • It simplifies integration by breaking down the equation into manageable parts.
  • Gives immediate access to known integration rules, making it easier to solve without complex algebraic manipulations.
This method forms the foundation of solving numerous differential equations, providing a pathway to derive a general solution.
General Solution
After applying the method of separation of variables to our differential equation, the next step is to find the general solution. The general solution of a differential equation includes an arbitrary constant, representing a family of solutions instead of a single specific answer.

The integration of both sides results in:
  • The left side \( \int dy = y \)
  • The right side \( \int \frac{1}{x} \, dx = \ln|x| \, + \, C \)

Hence, we arrive at the general solution \( y = \ln|x| + C \). This solution implies that the function \( y \) is dependent on the logarithmic function of \( x \), but modified according to the constant \( C \).

The concept of a general solution is crucial in differential equations as it provides the entire spectrum of possible answers. Any choice of \( C \) will satisfy the differential equation, allowing flexibility based on specific conditions or initial values that may later be given.
Integration Constant
An integration constant, denoted by \( C \), emerges from the process of integration within the solution of a differential equation. It represents an arbitrary constant added to ensure that all potential solutions are covered.

In our scenario where \( y = \ln|x| + C \), \( C \) accounts for the differences in initial conditions or sub-conditions which might be applied later. In essence:
  • \( C \) stabilizes the solution, making it adaptable to different scenarios.
  • It ensures that the solution includes all functions that are derivatives of the same integrand.

For example, if we have additional information such as a point through which the solution passes, we can utilize \( C \) to satisfy these particulars.

Ultimately, this constant highlights the variability and adaptability of solutions within differential contexts, emphasizing the capability of mathematics to tailor general expressions into specific, real-world applications.

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Most popular questions from this chapter

Evaluate the definite integrals exactly \([as in \)\ln (3 \pi)]\(,\) using the Fundamental Theorem, and numerically \([\ln (3 \pi) \approx 2.243]\) $$\int_{2}^{5}\left(x^{3}-\pi x^{2}\right) d x$$

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