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Find an antiderivative. $$h(t)=\cos t$$

Short Answer

Expert verified
The antiderivative of \(h(t) = \cos t\) is \(H(t) = \sin t + C\).

Step by step solution

01

Understand the Concept

An antiderivative of a function is a function whose derivative is the original function. In this case, we need to find the antiderivative of \(h(t) = \cos t\). This means we need to find a function \(H(t)\) such that \(H'(t) = \cos t\).
02

Recall the Antiderivative of Cosine

The antiderivative of the cosine function \(\cos t\) is the sine function \(\sin t\) because the derivative of \(\sin t\) is \(\cos t\).
03

Add the Constant of Integration

The antiderivative of a function is not unique because the derivative of a constant is zero. Therefore, we add a constant of integration, \(C\), to our antiderivative. This gives us \(H(t) = \sin t + C\).
04

Write the Final Antiderivative

The antiderivative of \(h(t) = \cos t\) is \(H(t) = \sin t + C\), where \(C\) is any constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosine Function
The cosine function, often represented as \( \cos t \), is a fundamental part of trigonometry and is primarily used to describe the horizontal coordinate of a point on the unit circle. When you see \( \cos t \), it tells you how far along the "x-axis" a point is from the center of a circle with a radius of 1. This function cycles every \( 2\pi \) radians, meaning it will return to the same value after a complete circle. This cyclical nature makes the cosine function very useful in modeling periodic phenomena, such as sound waves or the change of seasons.

  • The highest point the cosine function reaches is 1.
  • The lowest point it reaches is -1.
  • It is zero at \( \pi/2 \) and \( 3\pi/2\) radians, where the horizontal distance is zero.
Overall, knowing the properties of the cosine function is crucial for understanding how it transforms and how its antiderivative, the sine function, behaves.
Sine Function
The sine function, expressed as \( \sin t \), is closely related to the cosine function but represents the vertical coordinate of a point on the unit circle. It tells us how far above or below the center of the circle a point is, also cycling every \( 2\pi \) radians. Recognizing that the sine function is the antiderivative of the cosine function is a key insight in calculus, since it illustrates how these trigonometric functions are deeply interconnected.

The process of finding an antiderivative is the reverse of differentiation. Since the derivative of the sine function is the cosine function, integrating the cosine function gives us the sine function.
  • The sine function reaches 1 at \( \pi/2 \) radians.
  • It reaches -1 at \( 3\pi/2 \) radians.
  • The sine function is zero at 0 and \( \pi \) radians, where the vertical distance is zero.
This interplay between sine and cosine is foundational in calculus and trigonometry alike.
Constant of Integration
When we compute the antiderivative of a function, we must remember to include the constant of integration, typically denoted as \( C \). This is because differentiation and integration are inverse processes. While differentiating a constant yields zero, when integrating, any constant that may have been originally present is accounted for by adding a constant of integration.

For example, if \( H(t) = \sin t + C \), then the derivative \( H'(t) = \cos t \), aligning with our original function \( h(t) = \cos t \). Without this constant \( C \), the antiderivative would not be a complete representation of all possible original functions.
  • It captures all infinite possible shifts along the vertical axis that the sine function could have.
  • This constant makes the antiderivative a family of functions, not just a single function.
Always including the constant \( C \) in integrals ensures we account for every potential constant that differentiates to zero, thus maintaining the integrity of the original antiderivative process.

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Are the statements true or false? Give an explanation for your answer. Every continuous function has an antiderivative.

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