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In Exercises \(1-11,\) find the limit. Use I'Hopital's rule if it applies. $$\lim _{x \rightarrow 0} \frac{\sin x}{e^{x}}$$

Short Answer

Expert verified
The limit is 0.

Step by step solution

01

Evaluate Indeterminate Form

First, substitute \(x = 0\) into the expression \(\frac{\sin x}{e^x}\) to check if it is an indeterminate form.\[\frac{\sin(0)}{e^{0}} = \frac{0}{1} = 0\]The expression results in \(0\), so it isn't an indeterminate form such as \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\). Therefore, the limit can be directly evaluated.
02

Direct Evaluation of the Limit

Since the expression is not indeterminate, directly evaluate the limit.\[\lim _{x \rightarrow 0} \frac{\sin x}{e^{x}} = \frac{\sin(0)}{e^{0}} = \frac{0}{1} = 0\]Thus, the limit is \(0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits
Limits are a fundamental concept in calculus that help us understand the behavior of functions as they approach specific points. When we talk about a limit, we mean the value that a function approaches as the input (or "x" value) gets closer to some specific number. Knowing limits allows us to work with functions that we cannot easily simplify or calculate directly.

For instance, consider a situation where you have a function like \( \lim_{x \to c} f(x) = L \). This notation means that as \( x \) approaches \( c \), the function \( f(x) \) is getting closer and closer to \( L \).

In practice, finding limits involves substitution first; substituting the point into the function to check if it results in a meaningful number. If the result is a continuous function at that point, then the limit is simply the value of the function at that point. When substitution doesn't work directly, that's when we explore special techniques, such as factoring, rationalizing, or using calculus rules like L'Hopital's Rule.

Understanding the concept of limits is essential for solving more complex calculus problems, where the function's behavior around key points defines the outcome.
L'Hopital's Rule
L'Hopital's Rule is a useful tool for finding limits, especially when direct substitution doesn't work because you encounter an indeterminate form. This rule provides a way to differentiate and simplify the expressions until you reach a determinate form.

If you have a limit that results in an indeterminate form like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), L'Hopital's Rule says you can take the derivative of the numerator and the denominator separately and then calculate the limit again. The basic steps are:
  • Check for an indeterminate form like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\).
  • If such a form exists, differentiate the numerator and the denominator.
  • Recalculate the limit using the new function expressions.
  • If necessary, repeat until the limit is no longer indeterminate.
Remember, L'Hopital's Rule can only be applied under specific conditions when the original function is indeterminate. It's a critical technique that simplifies the work involved in evaluating complex limits by allowing you to use differentiation to clarify these unclear situations.
Indeterminate Forms
Indeterminate forms occur when attempting to evaluate a limit results in an expression that does not directly indicate a specific value. Common indeterminate forms include \(\frac{0}{0}\), \(\frac{\infty}{\infty}\), and others like \(\infty - \infty\) or \(0 \times \infty\). These forms suggest that the behavior of the function near the point is not clear and requires further manipulation to find a limit.

When you encounter an indeterminate form, it's like being at a dead end with the direct approach— it shows that more work needs to be done. Techniques like factoring, multiplying by conjugates, and especially L'Hopital's Rule are common approaches to resolve these indeterminate forms.

In the given exercise, evaluating the limit didn't lead to an indeterminate form, which showed that direct evaluation without L'Hopital's Rule was sufficient. However, recognizing these forms is crucial. It tells us when we need to apply special calculus techniques to work around obstacles and find a correct solution.

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