Chapter 2: Problem 25
Are the statements true or false? If a statement is true, give an example illustrating it. If a statement is false, give a counterexample. If a function is not continuous, then it is not differentiable.
Short Answer
Expert verified
True; a discontinuous function cannot be differentiable.
Step by step solution
01
Understanding Definitions
A function is differentiable at a point if it has a derivative there, and it must also be continuous at that point for the derivative to exist. Differentiability implies continuity.
02
Recognizing Continuity Condition
If a function is not continuous at a point, it may or may not have a derivative at that point, as continuity is required for differentiability.
03
Applying the Logic
Assuming a function is not continuous at a specific point, it cannot have a derivative there. Thus, if a function is not continuous, it cannot be differentiable.
04
Confirming with a Counterexample
Consider the function \( f(x) = \begin{cases} x^2, & \text{if } x eq 0 \ 1, & \text{if } x = 0 \end{cases} \). This function is not continuous at \( x = 0 \) as there is a jump, so it does not have a derivative at \( x = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity
In calculus, a function is said to be continuous at a particular point if you can draw it at that point without lifting your pencil from the paper. More formally, a function \( f(x) \) is continuous at a point \( x = a \) if the following three conditions are met:
A function that is not continuous may have a jump, a hole, or even become infinite at that point. This discontinuity means that you cannot smoothly move from one side of the point to the other. Understanding continuity is crucial because it is a foundational concept tied to many other topics in calculus, such as differentiability.
- \( f(a) \) must be defined.
- The limit of \( f(x) \) as \( x \) approaches \( a \) must exist. In other words, \( \lim_{x \to a} f(x) \) exists.
- The limit of \( f(x) \) as \( x \) approaches \( a \) must equal the value of the function at that point, i.e., \( \lim_{x \to a} f(x) = f(a) \).
A function that is not continuous may have a jump, a hole, or even become infinite at that point. This discontinuity means that you cannot smoothly move from one side of the point to the other. Understanding continuity is crucial because it is a foundational concept tied to many other topics in calculus, such as differentiability.
Differentiability
Differentiability is a step further from continuity. If a function is differentiable at a point, it means you can find a specific tangent line at that point, also known as the derivative. For a function \( f(x) \) to be differentiable at a point \( x = a \), it must first be continuous at that point. This condition is paramount because differentiability implies continuity, but not vice versa. Here are the essentials to check if a function is differentiable at a point:
When a function is differentiable at a point, it also means the rate of change is consistent and predictable there. If a function is not differentiable at a point, it may have a cusp, corner, or vertical tangent at that point.
- Ensure the function is continuous at the point.
- Check the limit definition of the derivative exists: \( \lim_{h \to 0} \frac{f(a + h) - f(a)}{h} \) must exist.
When a function is differentiable at a point, it also means the rate of change is consistent and predictable there. If a function is not differentiable at a point, it may have a cusp, corner, or vertical tangent at that point.
Counterexample
A counterexample is a specific case which demonstrates that a general statement is false. For the statement "If a function is not continuous, then it is not differentiable," a counterexample solidifies the argument. Consider the function \( f(x) \) defined as:
\[ f(x) = \begin{cases} x^2, & \text{if } x eq 0 \ 1, & \text{if } x = 0 \end{cases} \] Here, \( f(x) \) is not continuous at \( x = 0 \) because there is a jump discontinuity—\( f(x) \) abruptly changes from \( x^2 \) to \( 1 \). Consequently, \( f(x) \) cannot have a derivative at \( x = 0 \), thus it is not differentiable there. Counterexamples are crucial in mathematics as they help prove the limits of statements by showing exceptions or conditions under which a statement does not hold true.
\[ f(x) = \begin{cases} x^2, & \text{if } x eq 0 \ 1, & \text{if } x = 0 \end{cases} \] Here, \( f(x) \) is not continuous at \( x = 0 \) because there is a jump discontinuity—\( f(x) \) abruptly changes from \( x^2 \) to \( 1 \). Consequently, \( f(x) \) cannot have a derivative at \( x = 0 \), thus it is not differentiable there. Counterexamples are crucial in mathematics as they help prove the limits of statements by showing exceptions or conditions under which a statement does not hold true.
Derivative
The derivative of a function gives us the rate at which the function's output changes as its input changes. It is a foundational tool in calculus, often representing instantaneous rate of change or the slope of the function at a given point. Mathematically, the derivative of a function \( f(x) \) at a point \( x \) is defined as:
\[ f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} \]
Here are some important points regarding derivatives:
Understanding derivatives allows us to tackle a range of practical problems, from calculating motion to optimizing functions in business and science.
\[ f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} \]
Here are some important points regarding derivatives:
- If a function is differentiable at a point, it is also continuous at that point.
- The derivative can be understood visually as the slope of the tangent line to the function's graph at a point.
- It provides critical insight into the function's behavior, such as identifying whether the function is increasing or decreasing.
Understanding derivatives allows us to tackle a range of practical problems, from calculating motion to optimizing functions in business and science.