Chapter 2: Problem 31
A function \(f\) has \(f(5)=20, f^{\prime}(5)=2,\) and \(f^{\prime \prime}(x) < 0\) for \(x \geq 5 .\) Which of the following are possible values for \(f(7)\) and which are impossible? (a) 26 (b) 24 (c) 22
Short Answer
Expert verified
Possible: 22, 24. Impossible: 26.
Step by step solution
01
Understand Given Information
We know that the function \( f \) satisfies \( f(5) = 20 \), \( f'(5) = 2 \), and \( f''(x) < 0 \) for \( x \geq 5 \). This means the function is decreasing in concavity (concave down) from \( x = 5 \) onwards.
02
Analyze the Meaning of Concavity
The condition \( f''(x) < 0 \) for \( x \geq 5 \) implies that the slope of the function \( f(x) \) is decreasing. Thus, even if \( f' \) is initially positive at \( x = 5 \), it must decrease as \( x \) increases.
03
Evaluate Slope Change Over the Interval
At \( x = 5 \), the slope \( f'(5) = 2 \). As \( f''(x) < 0 \), the slope will decrease over the interval from \( x = 5 \) to \( x = 7 \). Therefore, the increase in value from \( f(5) \) to \( f(7) \) cannot be more than \( 2 \times 2 = 4 \) (using maximum slope before it decreases).
04
Calculate Potential Values for \( f(7) \)
Since \( f(5) = 20 \) and the slope at \( x = 5 \) is 2, the function might have initially increased by maximum \( 4 \) units to \( 24 \) at \( x = 7 \). Thus, \( f(7) = 24 \) is possible. However, \( f(7) = 26 \) requires an increase of 6 units, which is impossible as it assumes the slope remains \( 3 \) over an interval, which contradicts decreasing slope condition. \( f(7) = 22 \) involves an increase of only 2 units, so it's possible given slope must decrease.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
In mathematics, the derivative represents the rate at which a function is changing at any given point. It's essentially the slope of the function at a particular point. Imagine you're driving and looking at your speedometer - the speed is like the derivative, telling you how fast (or slow) you're moving at that moment. In our exercise, we see that the derivative at a specific point, \(x = 5\), is given as \(f'(5) = 2\). This tells us that at \(x=5\), the function's graph is rising at a rate of 2 units up for each unit you move to the right on the x-axis.
Key aspects of the derivative to note here are:
Key aspects of the derivative to note here are:
- Rate of change: Indicates how much the function increases or decreases.
- First Derivative: Provides information about the slope and is used to find where functions are increasing or decreasing.
Concave Down Function
A concave down function curves downward, like a frowning face. You can think of it as the arch of a bridge. When a function is concave down, any tangent line drawn at any point on the curve will always be above the curve. In the language of calculus, when the second derivative \(f''(x) < 0\), it tells us that the function is concave down.
In our exercise, the function is said to be concave down for \(x \geq 5\). This information is vital as it means:
In our exercise, the function is said to be concave down for \(x \geq 5\). This information is vital as it means:
- The slope of the function, derived from the first derivative \(f'(x)\), decreases as you move right along the x-axis.
- The maximum increase in \(f(x)\) can be calculated based on the initial slope, considering it can only decrease.
Second Derivative Test
The second derivative test is a handy tool in calculus to determine the curvature of a function and to find out where it is concave up or down. This test also helps identify possible inflection points - where the graph changes its direction of curvature.
To perform a second derivative test, you follow these steps:
To perform a second derivative test, you follow these steps:
- Calculate the second derivative of the function.
- Evaluate the second derivative at critical points.
- Check the sign of the second derivative:
- If \(f''(x) > 0\), the function is concave up (like a smile) at that point.
- If \(f''(x) < 0\), the function is concave down (like a frown) at that point.