Chapter 19: Problem 13
Solve the differential equation. \(y^{\prime}+(2 \cos x) y=\cos x\)
Short Answer
Expert verified
The solution is \( y = \frac{\sin(e^{2\sin x})}{e^{2\sin x}} + Ce^{-2\sin x} \).
Step by step solution
01
Identify the Type of Differential Equation
The given differential equation is \( y' + (2 \cos x)y = \cos x \). This is a first-order linear differential equation of the form \( y' + P(x)y = Q(x) \), where \( P(x) = 2\cos x \) and \( Q(x) = \cos x \).
02
Calculate the Integrating Factor
The integrating factor (\( \mu(x) \)) for a first-order linear differential equation is determined by \( \mu(x) = e^{\int P(x) \, dx} \). In this case, \( P(x) = 2 \cos x \), so we calculate:\[\mu(x) = e^{\int 2 \cos x \, dx} = e^{2 \sin x}.\]
03
Multiply the Equation by the Integrating Factor
Multiply the entire differential equation by the integrating factor \( e^{2 \sin x} \):\[ e^{2 \sin x}y' + 2\cos x e^{2 \sin x}y = \cos x e^{2 \sin x}. \]
04
Recognize and Reorganize Into Exact Derivative
Since we multiplied by the integrating factor, the left side of the equation becomes the derivative of \( e^{2 \sin x}y \):\[\frac{d}{dx}(e^{2 \sin x}y) = \cos x e^{2 \sin x}.\]
05
Integrate Both Sides
Integrate both sides with respect to \( x \):\[\int \frac{d}{dx}(e^{2 \sin x}y) \, dx = \int \cos x e^{2 \sin x} \, dx.\]This gives:\[ e^{2 \sin x}y = \sin(e^{2 \sin x}) + C, \]where \( C \) is the constant of integration.
06
Solve for y
To find \( y(x) \), divide both sides by \( e^{2 \sin x} \):\[y = \frac{\sin(e^{2 \sin x})}{e^{2 \sin x}} + Ce^{-2 \sin x}.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integrating Factor
When dealing with first-order linear differential equations, the integrating factor (\( \mu(x) \)) is a crucial tool to simplify and solve these equations. Such equations have the general form:
- \( y' + P(x)y = Q(x) \).
- \( \mu(x) = e^{\int P(x) \, dx} \).
Exact Derivative
An exact derivative arises when the left side of the differential equation, after being multiplied by the integrating factor, can be rewritten as the derivative of a product of functions. For the current exercise, after applying the factor \( e^{2 \sin x} \), the equation becomes:
- \( \frac{d}{dx}(e^{2 \sin x}y) = \cos x e^{2 \sin x} \).
Constant of Integration
When solving differential equations through integration, introducing a constant of integration, \( C \), is essential. This constant accounts for any constants that might have been present in the original function before differentiation. During integration, you will often see expressions like:
- \( e^{2 \sin x}y = \int \cos x e^{2 \sin x} \, dx + C \).