Chapter 19: Problem 22
Solve the differential equation. \(y^{\prime}+y \tan x=\cos ^{3} x\)
Short Answer
Expert verified
The solution is \( y = (\frac{1}{2}x + \frac{1}{4}\sin{2x} + C) \cos{x} \).
Step by step solution
01
Write the equation in standard form
The given differential equation is \( y^{\prime} + y \tan{x} = \cos^3{x} \). This can be compared to the standard form of a first-order linear differential equation: \( y' + P(x)y = Q(x) \). Here, \( P(x) = \tan{x} \) and \( Q(x) = \cos^3{x} \).
02
Find the integrating factor
To solve the equation, we need to find the integrating factor \( \mu(x) \), which is given by \( e^{\int P(x) \, dx} \). Therefore, compute \( \mu(x) = e^{\int \tan{x} \, dx} = e^{\ln|\sec{x}|} = |\sec{x}| \). Since \( \sec{x} \) is always positive over its domain, we have \( \mu(x) = \sec{x} \).
03
Multiply the equation by the integrating factor
Multiply the entire differential equation by the integrating factor to make the left-hand side a derivative of a product: \( \sec{x}y^{\prime} + \sec{x}y \tan{x} = \sec{x} \cos^3{x} \).
04
Simplify the left side
The left-hand side of the equation becomes \( \frac{d}{dx}(y \sec{x}) \) due to the integration property: \( \sec{x}y^{\prime} + y \sec{x} \tan{x} = \frac{d}{dx}(y \sec{x}) \).
05
Integrate both sides
Integrate both sides of the equation: \( \int \frac{d}{dx}(y \sec{x}) \, dx = \int \sec{x} \cos^3{x} \, dx \). The left side simplifies to \( y \sec{x} \) and the right side can be simplified to \( \int \cos^2{x} \, dx \) since \( \sec{x} \cos^3{x} = \cos^2{x} \).
06
Solve the integral
The integral \( \int \cos^2{x} \, dx \) is solved using \( \cos^2{x} = \frac{1+\cos{2x}}{2} \). Therefore, \( \int \cos^2{x} \, dx = \frac{1}{2}x + \frac{1}{4}\sin{2x} + C \), where \( C \) is the integration constant.
07
Solution of the equation
Equating both results, we have \( y \sec{x} = \frac{1}{2}x + \frac{1}{4}\sin{2x} + C \). Solving for \( y \), we get \( y = (\frac{1}{2}x + \frac{1}{4}\sin{2x} + C) \cos{x} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-Order Linear Differential Equations
First-order linear differential equations are equations that involve the first derivative of a function and can be expressed in the form: \[ y' + P(x)y = Q(x) \]Here,
- \( y' \) represents the derivative of \( y \) with respect to \( x \).
- \( P(x) \) and \( Q(x) \) are functions of \( x \).
Integrating Factor
The technique of using an integrating factor is vital for solving first-order linear differential equations. The integrating factor, often denoted as \( \mu(x) \), is a function used to multiply both sides of the differential equation which simplifies one side to an exact derivative.To find the integrating factor, use the formula:\[ \mu(x) = e^{\int P(x) \, dx} \]In our example,
- The equation \( y' + y \tan{x} = \cos^3{x} \) had \( P(x) = \tan{x} \).
- Thus, the integrating factor \( \mu(x) = e^{\int \tan{x} \, dx} = |\sec{x}| \).
Trigonometric Integration
Trigonometric functions often appear in differential equations, requiring specific techniques for integration. In our example, once the integrating factor \( \sec{x} \) was determined, the equation became:\[ \sec{x} y^{\prime} + y \sec{x} \tan{x} = \sec{x} \cos^3{x} \]This expression involves trigonometric functions, mainly \( \sec{x} \) and \( \cos^3{x} \), simplifying to \( \cos^2{x} \). Then, the integral:\[ \int \sec{x} \cos^3{x} \, dx = \int \cos^2{x} \, dx \]To solve this integral, one can use the identity:\[ \cos^2{x} = \frac{1 + \cos{2x}}{2} \]Integration leads to:
- \( \int \cos^2{x} \, dx = \frac{1}{2}x + \frac{1}{4}\sin{2x} + C \)
Solution Techniques for Differential Equations
When dealing with first-order linear differential equations, having a reliable solution technique is essential. The general steps to solve such equations involve:
- Rearranging the equation to fit the standard form: \( y' + P(x)y = Q(x) \)
- Calculating the integrating factor \( \mu(x) = e^{\int P(x) \, dx} \)
- Multiplying the entire equation by this integrating factor to simplify the left-hand side
- Integrating both sides