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For the following exercises, sketch the parametric curve and eliminate the parameter to find the Cartesian equation of the curve. \(x=1+t, \quad y=t^{2}-1, \quad-1 \leq t \leq 1\)

Short Answer

Expert verified
The Cartesian equation is \( y = x^2 - 2x \) for \( 0 \le x \le 2 \).

Step by step solution

01

Understanding the Problem

We are given parametric equations for a curve: \( x = 1 + t \) and \( y = t^2 - 1 \), with the parameter \( t \) restricted to \(-1 \leq t \leq 1\). Our tasks are to sketch this curve and eliminate the parameter \( t \) to find a Cartesian equation in terms of \( x \) and \( y \).
02

Solve for Parameter

From the equation \( x = 1 + t \), we solve for \( t \) by subtracting 1 from both sides: \( t = x - 1 \). We will use this expression for \( t \) to eliminate it from the parametric equations.
03

Substitute and Eliminate Parameter

Substitute \( t = x - 1 \) into the equation \( y = t^2 - 1 \). This gives:\[ y = (x-1)^2 - 1 \] This is the Cartesian equation of the curve.
04

Simplify the Cartesian Equation

Simplify the expression for \( y \):\[ y = (x-1)^2 - 1 \] becomes \[ y = x^2 - 2x + 1 - 1 \], which simplifies to \[ y = x^2 - 2x \].
05

Determine the Curve's Range

Given the range of \( t : -1 \leq t \leq 1 \), substitute the endpoints into \( x = 1 + t \) to find the range of \( x \). At \( t = -1, x = 0 \) and at \( t = 1, x = 2 \). Thus, the curve runs from \( x = 0 \) to \( x = 2 \).
06

Sketch the Curve

The curve described by the Cartesian equation \( y = x^2 - 2x \) is a parabola opening upwards. Plot the points at \( x = 0 \), \( x = 1 \), and \( x = 2 \) using \( y = x^2 - 2x \):- At \( x = 0 \): \( y = 0 \)- At \( x = 1 \): \( y = -1 \)- At \( x = 2 \): \( y = 0 \)Plot these points and draw a smooth parabola through them.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian equation
In mathematics, transforming parametric equations into a Cartesian equation is a useful technique. This process helps us express the relationship between variables without introducing a third, intermediary parameter.

To convert a parametric equation to a Cartesian equation, we follow a few steps:
  • Determine a way to express the parameter in terms of either variable.
  • Substitute that expression into the other equation.
  • Simplify the resulting expression to reveal a relationship solely between the two main variables.
In our exercise example, we began with the parametric equations:
\( x = 1 + t \) and \( y = t^2 - 1 \).
First, we solved for \( t \) in the \( x \) equation, giving us \( t = x - 1 \). Substituting \( t = x - 1 \) into the \( y \) equation yields the Cartesian form:
\[ y = (x-1)^2 - 1 \].
After simplifying, we arrive at the Cartesian equation \( y = x^2 - 2x \). This expresses the curve completely in terms of \( x \) and \( y \) and illustrates the foundational principle of removing parameters.
parabola
A parabola is a symmetrical curve on a plane, which can open upwards, downwards, leftwards, or rightwards. In a Cartesian coordinate system, a basic parabola can be represented by the equation:
\( y = ax^2 + bx + c \).
This equation indicates how the parabola is oriented and where it is located. The values of \( a \), \( b \), and \( c \) determine the direction and shape of the parabola.
  • If \( a > 0 \), the parabola opens upwards; if \( a < 0 \), it opens downwards.
  • The vertex of the parabola, where it turns direction, plays a crucial role in its shape. This can be found using \( x = -\frac{b}{2a} \).
  • The y-intercept occurs where the parabola crosses the y-axis, at point \( (0, c) \).
In our specific example, the Cartesian equation \( y = x^2 - 2x \) demonstrates a parabola opening upwards because the coefficient of \( x^2 \) is positive (1). By analyzing the terms, we infer the vertex formula reveals the vertex is at \( x = 1 \). This helps in sketching an accurate representation.
eliminate the parameter
Eliminating the parameter from parametric equations is a standard method to simplify and clarify relationships between variables. This approach focuses on removing the parameter, often denoted as \( t \), that we use to define a curve. By doing so, we derive what is known as a Cartesian or implicit equation.

The general steps include:
  • Isolating the parameter in one of the parametric equations.
  • Substituting this expression into the second equation.
  • Simplifying the resulting equation to connect the primary variables.
For the exercise provided, we had \( x = 1+t \) and \( y = t^2 - 1 \). Upon solving for \( t \) in the first equation, \( t = x - 1 \) was substituted into the second. This led us to simplify to find the Cartesian equation \( y = x^2 - 2x \). By following this process, the parameter \( t \) is effectively eliminated, leaving a direct connection between \( x \) and \( y \). This makes it easier to visualize and analyze the curve's properties.

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