Chapter 1: Problem 335
For the following exercises, find the equation of the tangent line to the given curve. Graph both the function and its tangent line. \(r=3+\cos (2 \theta), \quad \theta=\frac{3 \pi}{4}\)
Short Answer
Expert verified
The tangent line equation is formed using the slope from \( \frac{dy}{dx} \) and the point from \( \theta = \frac{3\pi}{4} \).
Step by step solution
01
Convert Polar Equation to Cartesian Coordinates
The given curve is in polar form: \( r = 3 + \cos(2\theta) \). To find the tangent line in a familiar Cartesian form, we first use the conversion formulas: \[ x = r \cos(\theta), \quad y = r \sin(\theta) \]Substitute \( r \) from the polar equation:\[ x = (3 + \cos(2\theta)) \cos(\theta), \quad y = (3 + \cos(2\theta)) \sin(\theta) \].
02
Differentiate to Find Slope of Tangent Line
Find \( \frac{dy}{d\theta} \) and \( \frac{dx}{d\theta} \) to acquire \( \frac{dy}{dx} \). The derivatives are:\[ \frac{dx}{d\theta} = \frac{d}{d\theta}((3 + \cos(2\theta)) \cos(\theta)) \]\[ \frac{dy}{d\theta} = \frac{d}{d\theta}((3 + \cos(2\theta)) \sin(\theta)) \].Use the product and chain rules to compute these expressions and then execute \( \frac{dy}{dx} = \frac{\frac{dy}{d\theta}}{\frac{dx}{d\theta}} \).
03
Evaluate Slopes at \(\theta = \frac{3\pi}{4}\)
Substitute \( \theta = \frac{3\pi}{4} \) into the expressions for \( \frac{dy}{d\theta} \) and \( \frac{dx}{d\theta} \) obtained before. Use these to evaluate \( \frac{dy}{dx} \), the slope of the tangent line at this angle.
04
Find the Point of Tangency
Compute the Cartesian coordinates of the point on the curve corresponding to \( \theta = \frac{3\pi}{4} \). Substitute in the polar equations:\[ r = 3 + \cos\left(2 \times \frac{3\pi}{4}\right) = 3 - \frac{1}{\sqrt{2}} \].Via \( x = r\cos(\theta) \) and \( y = r\sin(\theta) \), insert \( r \) and \( \theta \) to determine the precise point (\( x, y \)).
05
Form Equation of Tangent Line
Use the point-slope form of the equation of a line:\[ y - y_1 = m(x - x_1) \]where \( (x_1, y_1) \) is the point of tangency and \( m \) is the slope obtained. Substitute these values to write the equation of the tangent line.
06
Graph the Function and Tangent Line
On a graph, sketch the original curve using \( r = 3 + \cos(2\theta) \) and plot it. Add the tangent line at the point found using its linear equation. Confirm visually if the tangent is correct with respect to the curve's geometry.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates are a way of describing the position of a point in a plane. Unlike Cartesian coordinates that use a pair of values (x, y), polar coordinates use a radius and an angle, represented as \( (r, \theta) \).
- \( r \) is the distance from the origin to the point.
- \( \theta \) is the angle from the positive x-axis to the point.
Cartesian Coordinates
When dealing with equations of lines and curves, Cartesian coordinates are often more straightforward. This system uses two values, x and y, to describe a point in the plane. Converting polar equations into this familiar format can help simplify tasks like finding slopes and tangents.
To make this conversion from polar to Cartesian:
To make this conversion from polar to Cartesian:
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
Differentiation
Differentiation is a mathematical process used to compute the rate at which a quantity changes. In geometry, it's crucial for finding the slope of a curve at any given point. For our exercise, differentiation helps in determining the slope of the tangent line to the curve in Cartesian coordinates.
- To find the derivative of a function, you'd typically use rules like the power rule, product rule, or chain rule, depending on the form of the function.
- In this context, finding \( \frac{dy}{dx} \) involves differentiating \( x \) and \( y \) with respect to \( \theta \), and then taking the ratio \( \frac{dy/d\theta}{dx/d\theta} \).
Product Rule
The product rule is a fundamental differentiation technique used when dealing with functions that multiply each other. It's essential for our problem because the expressions for \( x \) and \( y \) derived from the polar format involve such products.
If you have two functions, \( u(\theta) \) and \( v(\theta) \), their derivative is given by:\[\frac{d}{d\theta}(u \cdot v) = u' \cdot v + u \cdot v'\]This means we must differentiate each function separately, then multiply each derivative by the other, uninfluenced function, and sum the results. When applied, this helps to accurately compute \( \frac{dx}{d\theta} \) and \( \frac{dy}{d\theta} \), integral steps in finding \( \frac{dy}{dx} \).
If you have two functions, \( u(\theta) \) and \( v(\theta) \), their derivative is given by:\[\frac{d}{d\theta}(u \cdot v) = u' \cdot v + u \cdot v'\]This means we must differentiate each function separately, then multiply each derivative by the other, uninfluenced function, and sum the results. When applied, this helps to accurately compute \( \frac{dx}{d\theta} \) and \( \frac{dy}{d\theta} \), integral steps in finding \( \frac{dy}{dx} \).
Chain Rule
The chain rule is an indispensable tool in calculus for differentiating composite functions. When a function is the result of multiple nested functions, the chain rule helps break it down.
For a function \( f(g(\theta)) \), the derivative with respect to \( \theta \) is:\[\frac{df}{d\theta} = \frac{df}{dg} \cdot \frac{dg}{d\theta}\]This rule is pivotal when differentiating expressions in our problem that depend on \( \cos(2\theta) \) or other non-linear transformations.
In analyses of curves like ours, using the chain rule helps to handle the inner complexities of trigonometric functions, ensuring accurate computation of slopes and lines.
For a function \( f(g(\theta)) \), the derivative with respect to \( \theta \) is:\[\frac{df}{d\theta} = \frac{df}{dg} \cdot \frac{dg}{d\theta}\]This rule is pivotal when differentiating expressions in our problem that depend on \( \cos(2\theta) \) or other non-linear transformations.
In analyses of curves like ours, using the chain rule helps to handle the inner complexities of trigonometric functions, ensuring accurate computation of slopes and lines.