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Let u, v and w be vectors in 3. Prove:

role="math" localid="1649919341939" u(v+w)=uv+uwand(u+v)w=uw+vw

(This is Theorem 10.29.)

Short Answer

Expert verified

Hence, we prove thatu(v+w)=uv+uwand(u+v)w=uw+vw

Step by step solution

01

Step 1. Given Information

Let u, v and w be vectors in 3. Prove:

u(v+w)=uv+uwand(u+v)w=uw+vw

02

Step 2. We have to prove u×(v+w)=u×v+u×w and (u+v)×w=u×w+v×w

Let u=(1,0,8),v=(0,1,6)andw=(1,9,3)

Firstly proving role="math" localid="1649920209467" u(v+w)=uv+uw

Now finding the value of u(v+w)

role="math" localid="1649921394781" u(v+w)=(1,0,-8)(0,1,6)+(-1,9,3)u(v+w)=(1,0,-8)(0+(-1),1+9,6+3)u(v+w)=(1,0,-8)(-1,10,9)u(v+w)=ijk10-8-1109u(v+w)=i0-8109-j1-8-19+k10-110u(v+w)=i(9-(-80))-j(9-8)+k(10-0)u(v+w)=89i-j+10k

03

Step 3. Now finding the value of u×v+u×w

uv+uw=ijk10-8016+ijk10-8-193uv+uw=i0-816-j1-806+k1001+i0-893-j1-8-13+k10-19uv+uw=i(6-(-8))-j(6-0)+k(1-0)+i(0-(-72))-j(3-8)+k(9-0)uv+uw=14i-6j+k+72i+5j+9kuv+uw=89i-j+10k

Now we prove thatu(v+w)=uv+uw

04

Step 4. Now proving (u+v)×w=u×w+v×w

Firstly finding the value of (u+v)w

role="math" localid="1649922089509" (u+v)w=(1,0,-8)+(0,1,6)(-1,9,3)(u+v)w=(1+0,0+1,-8+6)(-1,9,3)(u+v)w=(1,1,-2)(-1,9,3)(u+v)w=ijk11-2-193(u+v)w=i1-293-j1-2-13+k11-19(u+v)w=i(3-(-18))-j(3-2)+k(9-(-1))(u+v)w=21i-j+10k

05

Step 3. Now finding the value of u×w+v×w

uw+vw=ijk10-8-193+ijk016-193uw+vw=i0-893-j1-8-13+k10-19+i1693-j06-13+k01-19uw+vw=i(0-(-72))-j(3-8)+k(9-0)+i(3-54)-j(0-(-6))+k(0-(-1))uw+vw=72i+5j+9k+51i-6j+kuw+vw=21i-j+10k

Now we prove that(u+v)w=uw+vw

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