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In Exercises 22鈥29 compute the indicated quantities when u=(2,1,3),v=(4,0,1),andw=(2,6,5)

vwandwv

Short Answer

Expert verified

The value ofvw=-6i+22j+24kandwv=6i-22j-24k.

Step by step solution

01

Step 1. Given Information 

In Exercises 22鈥29 compute the indicated quantities whenu=(2,1,3),v=(4,0,1),andw=(2,6,5)

We have to find the value ofvwandwv

02

Step 2. Firstly finding the value of v×w

The value of vectorsv=(4,0,1),andw=(2,6,5)

The cross product ofrole="math" localid="1649399442305" vw=detijk401-265

03

Step 3. Now solving the matrix. 

vw=detijk401-265vw=((0)(5)(1)(6))i+((4)(5)(1)(-2))j+((4)(6)(0)(-2))kvw=(0-6)i+(20+2)j+(24+0)kvw=-6i+22j+24k

04

Step 4. Firstly finding the value of w×v

The value of vectorsv=(4,0,1),andw=(2,6,5)

The cross product ofvw=detijk401-265

05

Step 5. Now solving the matrix. 

wv=detijk-265401wv=((6)(1)(5)(0))i+((-2)(1)(5)(4))j+((-2)(0)(6)(4))kwv=(6-0)i+(-2-20)j+(0-24)kwv=6i-22j-24k

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