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91Ó°ÊÓ

Use the given acceleration vectors a(t)=v(t)=r(t)and initial conditions in Exercises to find the position function r(t).

localid="1650040775983" a(t)=−32j,v(0)=5i+5j,r(0)=26j

Short Answer

Expert verified

at=-32j,v0=5i+5j,r0=26j

rt=5ti+1-16t2+5t+26j

Step by step solution

01

Given Information

Consider, at=-32j,v0=5i+5j,r0=26j

The objective is to find the position function r(t)

since

at=v2t=r2t,Wehavevt=∫atdtandrt=∫vtdtnowvt=∫atdt=∫-32jdtv0=c1i+c2j............(1)v0=5i+5j............(2)

02

Calculation

Comparing(1) and (2) equations,

c1=5,c2=5

so,

vt=5i+-32t+5jrt=∫vtdt=∫5i+-32i+5jdt

Where Cis a vector constant

=5i+c3i+-16t2+5t+c4j

Where C3and C4are scalars

r0=26jthus,rt=5ti+1-16t2+5t+26j

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