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Let x1t, x2t, y1t, and y2tbe differentiable scalar functions. Prove that the dot product of the vector-valued functions role="math" localid="1649579098744" r1t=x1t,y1tand role="math" localid="1649579122624" r2t=x2t,y2tis a differentiable scalar function.

Short Answer

Expert verified

The dot product of the vector-valued functions r1t=x1t,y1t and r2t=x2t,y2t is a differentiable scalar function.

Step by step solution

01

Step 1. Given information

We have to prove that the dot product of the vector-valued functions r1t=x1t,y1tand r2t=x2t,y2tis a differentiable scalar function.

02

Step 2. Proof of the question.

r1t·r2t=x1t,y1t·x2t,y2t=x1ti+y1tj·x2ti+y2tj=x1tx2ti·i+x1ty2ti·j+y1tx2tj·i+y1ty2tj·j=x1tx2t+y1ty2t

Therefore,

r1t·r2t=x1tx2t+y1ty2t, is a scalar function.

The product and sum of differentiable functions are differentiable.

Since x1tand x2tare differentiable⇒x1tx2tis differentiable.

y1t,y2tare differentiabley1ty2tis differentiable.

Finally,

x1tx2t+y1ty2tis differentiable.

Hence r1t·r2tis a differentiable scalar function.

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