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Let r(t) be a differentiable vector function such that r(t)·r'(t)=0 for every value of t. Prove that ‖r(t)‖ is a constant.

Short Answer

Expert verified

Ans:

ddt‖r‖2=ddt(r·r)=rddt(r)+rddt(r)=0

Step by step solution

01

Step 1. GIven information: 

Consider a differentiable vector function r(t) such that r(t)·r'(t)=0 For every value of t.

02

Step 2. Proving:

Consider

ddt‖r‖2=ddt(r·r)sicne‖r‖2=r·r=rddt(r)+rddt(r)Derivativeforproductof2functions

=r·r'+r·r'drdr=r'=2r·r'add=2(0)sincer·r'=0=0Multiplyddt‖r‖2=0. That means‖r‖is a constant, since the derivative of a constant is zero.

Thus ‖r(t)‖is a constant if r(t)·r'(t)=0

Note: The converse is always true. That is, if r(t)is a differentiable vector function such that ‖r(t)‖is a constant then r(t)·r'(t)=0.

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