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91Ó°ÊÓ

For each of the vector-valued functions, find the unit tangent vector.

r(t2)=(t2+5,5t,4t3)

Short Answer

Expert verified

1144t4+4t2+252t,5,12t2

Step by step solution

01

Step1. Given Information

Considerr(t)=t2+5,5t,4t3The objective is to find the unit tangent vector tor(t)The unit tangent vectorThe unit tangent vector ofr(t)denoted byT(t)is defined asT(t)=r′(t)r′(t)Considerr(t)=t2+5,5t,4t3First we computer′(t):r′(t)=ddtt2+5,5t,4t3=ddtt2+5,ddt(5t),ddt4t3=2t,5,12t2r′(t)=2t,5,12t2=(2t)2+(5)2+12t22=4t2+25+144t4

02

Step2. Continue

The unit tangent vector tor(t)isT(t)=r′(t)r′â¶Ä²(t)=2t,5,12t24t2+25+144t4=1144t4+4t2+252t,5,12t2Thus the unit tangent vector to the given vector function is1144t4+4t2+252t,5,12t2

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