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Find the curvature of each of the vector-valued functions defined in Exercises 39鈥44.

r(t)=tsint,tcost,t,whereisaconstant

Short Answer

Expert verified

The curvature of the given vector-valued function is=t4+4+2t2+4+42t2+1+23.

Step by step solution

01

Step 1. Given Information. 

The given vector-valued function isr(t)=tsint,tcost,t,whereisaconstant.

02

Step 2. Find the curvature. 

To find the curvature of the given vector-valued function, we will use the formula for the Curvature of a Space Curve=r'tr''tr't3.

So,

r(t)=tsint,tcost,tr'(t)=tcost+sint,-tsint+cost,r''(t)=-tsint+2cost,-tcost-2sint,0Now,r'(t)r''(t)=ijktcost+sint-tsint-tsint+2cost-tcost-2sint0=itcost+2sint-jtsint-2cost+k-t2-2=tcost+2sint,tsint-2cost,-t2-2Let'sfindr'(t)r''(t)=tcost+2sint2+-tsint+2cost2+-t2-22=t4+4+2t2+4+42.........(a)Andr'(t)=tcost+sint2+-tsint+cost2+2=t2+1+2........(b)

03

Step 3. Calculate.   

Put the values of (a) and (b) in the formula of Curvature of a space curve,

=t4+4+2t2+4+42t2+1+23=t4+4+2t2+4+42t2+1+23

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Most popular questions from this chapter

For each of the vector-valued functions, find the unit tangent vector.

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