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91Ó°ÊÓ

Evaluate the integrals in Exercises 40–44.

∫t,t2,t3dt

Short Answer

Expert verified

The value for the given vector function ist22,t33,t44+C.

Step by step solution

01

Step 1. Given Information

Given that,∫t,t2,t3dt.

Let us assume r(t)=t,t2,t3

02

Step 2. Evaluating the given integral

Evaluation,

∫r(t)dt=∫t,t2,t3dt=∫(ti+t2j+t3k)dt=i∫tdt+j∫t2dt+k∫t3dt=i(t22)+j(t33)+k(t44)+C=t22,t33,t44+C

So, the value of the given vector function ist22,t33,t44+C.

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