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91Ó°ÊÓ

Find the velocity and acceleration vectors for the position vectors given in Exercises 30–34

33.r(t)=⟨sint,cost,2sin2t⟩

Short Answer

Expert verified

The velocity and acceleration vectors are;

v(t)=⟨cost,−sint,4cos2t⟩a(t)=⟨−sint,−cost,−8sin2t⟩

Step by step solution

01

Step 1. Given data

The given position vector isr(t)=⟨sint,cost,2sin2t⟩

We have to find the velocity and acceleration vectors.

02

Step 2. Velocity vector

The velocity vector v(t) is given by

v(t)=ddtr(t)=⟨ddtx(t),ddty(t),ddtz(t)⟩

Therefore,

v(t)=ddtr(t)=ddt⟨sint,cost,2sin2t⟩=⟨ddtsint,ddtcost,ddt2sin2t⟩=⟨cost,−sint,4cos2t⟩

Hence the velocity vectorv(t)=⟨cost,−sint,4cos2t⟩

03

Step 3. Acceleration vector

The acceleration vector a(t) is given by

a(t)=ddtv(t)

Therefore,

a(t)=ddtv(t)=ddt⟨cost,−sint,4cos2t⟩=⟨ddt(cost),ddt−sint,ddt4cos2t⟩=⟨−sint,−cost,−8sin2t⟩

Hence the acceleration vectora(t)=⟨−sint,−cost,−8sin2t⟩

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