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Find the velocity and acceleration vectors for the position vectors given in Exercises 30鈥34

31.r(t)=teti+tlntj

Short Answer

Expert verified

The velocity and acceleration vectors are;

v(t)=(t+1)et,1+lnta(t)=(t+2)et1t

Step by step solution

01

Step 1. Given data

The given position vector isr(t)=teti+tlntj

We have to find the velocity and acceleration vectors.

02

Step 2. Velocity vector

The velocity vector v(t) is given by

v(t)=ddtr(t)=x(t)i+y(t)j+z(t)k=x(t),y(t),z(t)

Therefore,

v(t)=ddt(r(t))=ddt(teti+tlntj)=ddt(tet)i+ddt(tlnt)j=(tet+et)i+(1+lnt)j=(t+1)ei+(1+lnt)j=(t+1)et,1+lnt

Hence the velocity vectorv(t)=(t+1)et,1+lnt

03

Step 3. Acceleration vector

The acceleration vector a(t) is given by

a(t)=ddtv(t)=x鈥测赌(t)i+y鈥测赌(t)j+z鈥测赌(t)k=z鈥测赌(t),y鈥测赌(t),zn(t)

Therefore,

a(t)=ddt(v(t))=ddt(t+1)et,1+lnt=ddt(t+1)et,ddt(1+lnt)=(t+1)et+et,1t=(t+1+1)et,1t=(t+2)et1t

Hence the acceleration vectorlocalid="1649664589547" a(t)=(t+2)et1t

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