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Given a vector-valued function r(t) with domain , what is the relationship between the graph of r(t) and the graph of kr(t), where k > 1 is a scalar?

Short Answer

Expert verified

The relationship between the graph of r(t) and the graph of kr(t), where k > 1 is a scalar is that the arc length of the function will become ktimes.

Step by step solution

01

Step 1. Given Information. 

The given vector-valued functionr(t) has a domain.

02

Step 2. Explanation. 

Let a vector-valued function r(t) inisr(t)=cost,sint,t,t0,2.

So, the graph of r(t)is

The arc length of the curve we get by the graph isl=22.

03

Step 3. Explanation. 

Now, multiply by scalar k,so kr(t)=kcost,ksint,kt,t0,2.

Take k=7,sokr(t)=7cost,7sint,7t.

So, the graph is

Now, the arc length of the curve by the graph is l=142.

So, we can depict by the graphs and arc lengths that the arc length of the function will becomek times.

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