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Explain why the graph of every vector-valued function r(t)=cost,sint,f(t)lies on the surface of the cylinder x2+y2=1for every continuous functionf.

Short Answer

Expert verified

The graph of every vector-valued functionr(t)=cost,sint,f(t) lies on the surface of the cylinder x2+y2=1 for every continuous function f because every point of r(t)satisfies the surface of the cylinder.

Step by step solution

01

Step 1. Given Information.

The given vector-valued function isr(t)=cost,sint,f(t), and the surface of the cylinder isx2+y2=1.

02

Step 2. Explanation.

To explain why the graph of every vector-valued function lies on the surface of the cylinder for every continuous function f,substitute x=costandy=sintin the given surface of the cylinder equation.

So,

x2+y2=1cos2t+sin2t=11=1

It is true.

Thus, every point of r(t)satisfies the given equation of the surface of the cylinder.

Hence the graph ofr(t)=cost,sint,f(t),lies on the surface of the cylinderx2+y2=1for every continuous functionf.

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