/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 41 Consider once again the notion o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider once again the notion of the rotation of a vector field. If a vector field F(x,y,z)has curl F=0at a point P, then the field is said to be irrotational at that point. Show that the fields in Exercises are irrotational at the given points.

F(x,y,z)=2xyz,x2z,x2y,P=(1,1,1)

Short Answer

Expert verified

It is proved that the Vector fieldF(x,y,z)is rotational at the pointP=(1,1,1).

Step by step solution

01

Vector field.

A vector field is an assigning of a vector to every point in a subset of space in vector calculus and physics. A vector field in the plane, for example, might be represented as a collection of arrows, including a certain magnitude and direction, each tied to a specific point in the plane.

02

The curl of Vector field.

Consider the vector field below:

F(x,y,z)=2xyz,x2z,x2y.

The goal is to demonstrate that the vector field is rotating atP=(1,1,1).

Irrotational:

in the case of a vector field F(x,y,z)If curl F=0at pointP, this field is referred to as irrotational at that location.

A vector field's curl is defined as follows:F(x,y,z)==F1(x,y,z),F2(x,y,z),F3(x,y,z)

CurlF(x,y,z)=ijk∂∂x∂∂y∂∂zF1(x,y,z)F2(x,y,z)F3(x,y,z)

=∂F3∂y-∂F2∂zi-∂F3∂x-∂F1∂zj+∂F2∂x-∂F1∂yk

03

prove that the vector field is irrotational at P.

The curl of vectorF(x,y,z)=2xyz,x2z,x2yis defined as follows:

CurlF(x,y,z)=ijk∂∂x∂∂y∂∂z2xyzx2zx2y

=∂x2y∂y-∂x2z∂zi-∂x2y∂x-∂(2xyz)∂zj+∂x2z∂x-∂(2xyz)∂yk

=x2-x2i-[2xy-2xy]j+[2xz-2xz]k

=0i+0j+0k=0

Note that the vector field:F(x,y,z)=2xyz,x2z,x2y;

CurlF=0

Hence, It is proved that the Vector fieldF(x,y,z)is rotational at the point P=(1,1,1).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.