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Show that the vector fields in Exercises 33–40 are not conservative.

G(x,y,z)=(3,yz,z+12)

Short Answer

Expert verified

The vector fields is not conservative because ∂F1∂z≠∂F2∂y..

Step by step solution

01

Step 1. Given Information

We have to show that the vector fields in the given exercise is not conservative.
G(x,y,z)=(3,yz,z+12)

02

Step 2. A vector field G(x,y)=(G1(x,y),G2(x,y)) is not conservative if and only if ∂F1∂z≠∂F2∂y.

For the vector fieldG(x,y,z)=(3,yz,z+12)

∂F1∂z=∂∂zyz∂F1∂z=y∂∂zz∂F1∂z=y

03

Step 3. Now finding ∂F2∂y

∂F2∂y=∂∂y(z+12)∂F2∂y=∂∂yz+∂∂y12∂F2∂y=0

Hence, ∂F1∂z≠∂F2∂y.

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