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Consider the function f(x)=2+tan-1xshown in the next figure.

(a) Find the average value of f(x)on -4,4.

(b) Find a valuec∈-4,4art whichf(x)achieves its average value.

Short Answer

Expert verified

Part (a). The average value is 2.

Part (b). The value of constant isc=0.

Step by step solution

01

Part (a) Step 1. Given information.

The given function isf(x)=2+tan-1x.

02

Part (a) Step 2. First, we solve the indefinite integral.

∫2+tan-1xdx=∫2dx+∫tan-1xdx=2x+tan-1x∫dx-∫ddxtan-1x∫dxdx=2x+tan-1x·x-∫1x2+1·xdx=2x+x·tan-1x-12∫1tdt⋯⋯⋯⋯⋯⋯⋯x2+1=t,2xdx=dt,xdx=12dt=2x+x·tan-1x-12lnt=2x+x·tan-1x-12lnx2+1⋯⋯⋯⋯t=x2+1

03

Part (a) Step 3. Now find the average value by using the formula.

The average value of a function is 1b-a∫abf(x)dx.

In this problem a=-4,b=4and f(x)=2+tan-1x.

14--4∫-442+tan-1xdx=182x+x·tan-1x-12lnx2+1-44=182(4)+4·tan-14-12ln42+1-182-4+(-4)·tan-1(-4)-12ln(-4)2+1=188+4·tan-14-12ln17-18-8+(-4)·tan-1(-4)-12ln17=188+8+4tan-14-4tan-14-12ln17+12ln17=18(16)=2

04

Part (b) Step 1. Given information.

The given function isf(x)=2+tan-1x.

05

Part (b) Step 2. Find a value c∈-4,4.

Favg=2+tan-1xx=c2=2+tan-1ctan-1c=0c=0

Hence, the required value ofcis0∈-4,4.

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