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Why does it make sense that ∫1∞1xpdx diverges when 0<p≤1 ? Consider how 1xp compares with 1x in this case.

Short Answer

Expert verified

The integral gives the indefinite result forp=1.

Step by step solution

01

Step 1. Given information.   

We are given,

∫1∞1xpdx

The integral diverges when 0<p≤1.

02

Step 2. Comparing the integral

When the integral ∫1∞1xpdxis solved in the interval 0<p≤1, it gives an result of ∞.

As when p=1is considered in the interval.

Then the resulting integral is lnxwhere the interval [∞,1]is applied which gives the indefinite result.

That's why the result is diverges.

In this case, 1xpis equal to 1xwhen p=1.

So,

∫1∞1xdx=[lnx]1x=ln∞-ln1=∞

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