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Solve the integral :∫xtan-1xdx

Short Answer

Expert verified

The required answer isx22tanx-1x-x2+12tan-1x+c.

Step by step solution

01

Step 1. Given information. 

We have given integral is ∫xtan-1xdx.

02

Step 2. Solve the integration by parts .  

We have,

u=tan-1xdu=dxx2+1

and

dv=xdxv=∫xdxv=x22

The formula of integration by parts is ∫udv=uv-∫vdu.

∫xtan-1xdx=tanx-1xx22-∫x221x2+1dx=x22tanx-1x-∫x22(x2+1)dx=x22tanx-1x-12∫1-1(x2+1)dx=x22tanx-1x-12∫1dx+12∫1(x2+1)dx=x22tanx-1x-x2+12tan-1x+c

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Most popular questions from this chapter

Which of the integrals that follow would be good candidates for trigonometric substitution? If a trigonometric substitution is a good strategy, name the substitution. If another method is a better strategy, explain that method.

(a)∫4+x2xdx (b)∫x4+x2dx

role="math" localid="1648759296940" (c)∫x24+x2dx (d)∫16−x44+x2dx

Solve the integral: ∫xlnx2dx

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The substitution x = 2 sec u is a suitable choice for solving∫1x2−4dx.

(b) True or False: The substitution x = 2 sec u is a suitable choice for solving∫1x2−4dx.

(c) True or False: The substitution x = 2 tan u is a suitable choice for solving∫1x2+4dx.

(d) True or False: The substitution x = 2 sin u is a suitable choice for solving∫x2+4−5/2dx

(e) True or False: Trigonometric substitution is a useful strategy for solving any integral that involves an expression of the form x2−a2.

(f) True or False: Trigonometric substitution doesn’t solve an integral; rather, it helps you rewrite integrals as ones that are easier to solve by other methods.

(g) True or False: When using trigonometric substitution with x=asinu, we must consider the cases x>a and x<-a separately.

(h) True or False: When using trigonometric substitution with x=asecu, we must consider the cases x>a and x<-a separately.

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