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Solve the integral: ∫xlnx2dx

Short Answer

Expert verified

The required answer isx2lnx-x22+c.

Step by step solution

01

Step 1. Given information. 

We have given integral is∫xlnx2dx.

02

Step 2. Solve the integration by parts . 

We have,

u=lnxdu=dxx

and

dv=xdxv=∫xdxv=x22

The formula of integration by parts is ∫udv=uv-∫vdu
∫xlnx2dx=2lnxx22-∫x22×1xdx=2lnxx22-∫x2dx=x2lnx-x22+c

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