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Solve each of the integrals. Some integrals require trigonometric substitution, and some do not. Write your answers as algebraic functions whenever possible.

∫x2+6x+18dx.

Short Answer

Expert verified

The value is,

92sinh-1x+33+94sinh2sinh-1x+33+C.

Step by step solution

01

Step 1. Given Information.

The integral is,

∫x2+6x+18dx.

02

Step 2. Simplifying the integral.

∫x2+6x+18dx=∫(x+3)2+9dx=∫u2+9du[u=x+3,du=dx]

To solve the integral, let u=3sinhv

Now,u=3sinhvdu=3coshvdv.

Using the identity,sinh2v+1=cosh2vwe find the values,

u2+9du=9sinh2v+9=3cosh2v

03

Step 3. Solving the integral.

The integral solution is,

∫u2+9du=∫9cosh2vdv=9∫12dv+9∫cosh22vdv=92v+92∫12coshwdw[w=2v,dw=2dv]=92v+94sinhw=92v+94sinh2v=92sinh-1u3+94sinh2sinh-1u3=92sinh-1x+33+94sinh2sinh-1x+33+C

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