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Complete the square for each quadratic in Exercises 28–33. Then describe the trigonometric substitution that would be appropriate if you were solving an integral that involved that quadratic.

x2−4x−8

Short Answer

Expert verified

The completing square of the given quadratic equation is x-22-12,and the appropriate trigonometric substitution isx-2=12secu.

Step by step solution

01

Step 1. Given Information.

The given quadratic isx2-4x-8.

02

Step 2. Completing the square for the given quadratic.

The complete square of the given quadratic equation is as follows:

x2-4x-8x2-4x+-22=8+22x2-4x+4=12x-22=12x-22-12

03

Step 3. Describing the trigonometric substitution.

After completing the square for the given quadratic equation it is in the form of x2-a2.

So, for solving an integral that involved the quadratic then the trigonometric substitution can be used is x=asecu.

Here, x=x-2anda=12.

Thus, the appropriate trigonometric substitution isx-2=12secu.

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