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In Exercises 43–46 give the first five terms for a geometric sequence crk,k=0with the specified values of candr.

c=3,r=12.

Short Answer

Expert verified

The first five terms are3,32,34,38,316.

Step by step solution

01

Step 1. Given information.

The given values arec=3,r=12.

02

Step 2. First term.

The general sequence is ak=crk.

On substituting the given values,

ak=(3)12k

For first term, k=0,

a0=(3)120=3

03

Step 3. Remaining terms.

Now, when,

k=1,a1=(3)12'=32k=2,a2=(3)122=34k=3,a3=(3)123=38k=4,a4=(3)124=316

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