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Let bbe a nonzero constant. Prove that the radius of convergence of the power series ∑k=0∞ bkxkis1|b|.

Short Answer

Expert verified

Ans: It is proved that the radius of convergence of the power series ∑k=0∞ bkxkis1|b|

Step by step solution

01

Step 1. Given information.

given,

∑k=0∞ bkxkis1|b|

02

Step 2. Consider the power series ∑k=0∞ bkxk , where b be a non-zero constant.

Also, let us consider bk=akxk,sobk+1=ak+1xk+1

Apply the ratio test for absolute convergence in the power series ∑k=0∞ bkxk, that is

limk→∞ bk+1bk=limk→∞ bk+1bkx=limk→∞ |bx|

So according to the ratio test for absolute convergence, the series will converge only when|bx|<1

Implies that |x|<1|b|


03

Step 3. Thus,

The radius of convergence of the power series ∑k=0∞ bkxkis1|b|

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