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91Ó°ÊÓ

In exercises 59-62 concern the binomial series to find the maclaurin series for the given function .

1+x3

Short Answer

Expert verified

The maclaurin series for the given function is

1+x3=1+13x−19x2+581x3+⋯

Step by step solution

01

Step 1.Given information 

We have been given

f(x)=1+x3

to find the maclaurin series by using binomial series

02

Step 2.Defining the series 

For any non- zero constant p, the Maclaurin series for the function g(x)=(1+x)pis called the binomial series which is given by ∑k=0∞ pkxkwhere the binomial coefficient is pkpk=p(p−1)(p−2)⋯(p−k+1)k!, â¶Ä…â¶Ä…â¶Ä…ifk>01, â¶Ä…â¶Ä…â¶Ä…ifk=0

03

Step 3. Binomial series for the given function is 

so for the given function f(x)=1+x3 , the binomial series is1+x3=∑k=0∞ 13kxk

this implies that ,

1+x3=130x0+131x1+132x2+133x3+⋯=1+13x+13−232!x2+13−23−533!x3+⋯=1+13x−19x2+581x3+⋯
04

Step 4. Finding the maclaurin series of given function 

Hence the maclaurin series of given function is

1+x3=1+13x−19x2+581x3+⋯

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