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In Exercises 49-54in Section 8.2you were asked to find the Taylor series for the specified function at the given value of x0. In Exercises 45-50find the Lagrange's form for the remainder Rn(x), and show that limnRn(x)=0on the specified interval.

cosx,2,

Short Answer

Expert verified

That, which isRn(x)=x-2n+1(n+1)!proved.

Step by step solution

01

Given Information

Let us consider the functionf(x)=cosx

02

Lagrange's Form

If f(x)=cosx, we know that for every n0,f(n+1)(x)is one of the four function sinxand cosx. So, for any of the four functions, f(n+1)(c)1, for every value of x, so using the Lagrange's form for the remainder, we have

Rn(x)=f(n+1)(c)(n+1)!xn+1

03

Proof

Since the Taylor series for the function f(x)=cosxat x=2is

Pn(x)=k=0(-1)n+1(2n+1)!x-22n+1

Therefore,

Rn(x)=x-2n+1(n+1)!

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