/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 45 In Exercises 41–50, find Macla... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 41–50, find Maclaurin series for the given pairs of functions, using these steps:

(a) Use substitution and/or multiplication and the appropriate Maclaurin series to find the Maclaurin series for the given function f .

(b) Use Theorem 8.12 and your answer from part (a) to find the Maclaurin series for the antiderivative F=∫fthat satisfies the specified initial condition

(a)f(x)=11+x3(b)F(0)=-5

Short Answer

Expert verified

Part (a) 11+x3=∑(-1)kk=0∞x3k

Part (b)F(x)=∑k=0∞-1kx3k+13k+1-5

Step by step solution

01

Part (a) Step 1. Given information

Let us consider the given functionf(x)=11+x2

02

Part (a) Step 2. Use substitution and/or multiplication and the appropriate Maclaurin series to find the Maclaurin series for the given function f .

The maclaurin series for g(x)=11-xis :

11-x=∑k=0∞x4

So,the maclaurin series for f(x)=11+x3can be founded by substituting xbyx3

Thus,

role="math" localid="1650698112599" 11+x3=∑k=0∞-x3k=∑(-1)kk=0∞x3k

03

Part (b) Step 1. Given information

Let us consider the given functionF=∫f(x)

04

Part (b) Step 2.  Use Theorem 8.12 and your answer from part (a) to find the Maclaurin series for theF=∫f antiderivative  that satisfies the specified initial condition 

Put the value of functionf(x)

role="math" localid="1650698386934" F(x)=∫∑k=0∞-1kx3kdx=∑k=0∞-1k∫x3kdx=∑k=0∞-1kx3k+13k+1+C

Since,the initial condition isF(0)=-5

This implies that:

C=-5

Therefore,

F(x)=∑k=0∞-1kx3k+13k+1-5

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.