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ind the Maclaurin series for e-x2, and use it to approximate ∫01e-x2dx to within 0.001 of its value. How many terms would you need to approximate the integral to within10-6 of its value?

Short Answer

Expert verified

The Maclaurin series can be given as

e-x2=1-x2+x42-x63!+x84!-...

On integrating we get,

∫01e-x2dx=1-13+110-142+1216-...

And we require first 6 terms to get corrected values upto 0.0001

Step by step solution

01

Given information

We are given the power series ofex

02

Find the power series of e-x2

We know the Maclaurin series of exwhich can be given as

role="math" localid="1654420433127" ex=1+x+x22+x33!+x44!+...substitutex=-x2e-x2=1-x2+x42-x63!+x84!-...Nowintegrating∫01e-x2dx=∫011-x2+x42-x63!+x84!-...dx∫01e-x2dx=[x-x33+x510-x742+x9216-......]10∫01e-x2dx=1-13+110-142+1216-...

We reuqire first 6 terms to get values corrected upto 0.0001 of its value

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